The complete question is
Susan and Steven are cousins. The sum of their ages is 33. The difference between three times Steven's age and half of Susan's age is 36. Find <span>the age of Susan and Steven
let
x-----> </span>Susan's age
y----> Steven's age
we know that
y+x=33-----> equation 1
3y-x/2=36----> multiply by 2----> 6y-x=72----> equation 2
adds equation 1 and equation 2
y+x=33
6y-x=72
-------------+
7y=105--------> y=15
x=33-y----> x=33-15----> x=18
the answer is
Susan's age is 18
Steven's age is 15
56 ounces are 3.5 pounds because 16 ounces are 1 pound and if you divide 56 by 16 you get 3.5
R = laps she runs
s = laps she swims
each r (laps she runs) takes 5 min.
each s (laps she swims) takes 3 min.
She wants to run for 30 min.
So your inequality should = 30
Answer:
B. y ≤ |x – 2| + 4
Step-by-step explanation:
Shading is <em>below</em> the <em>solid</em> line, so the appropriate relation symbol is "less than or equal to" (≤).
Shading is <em>below</em> when y values less than those on the line are part of the solution set.
The line is <em>solid</em> when it is part of the solution set (dashed, otherwise). It is part of the solution set when y-values <em>equal to</em> those on the line are solutions to the inequality.
The zeros are at -3, 1 and 3
