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Tatiana [17]
3 years ago
5

Does anyone have the rest of the test? Surface Area and Volume Unit Test????

Mathematics
1 answer:
jarptica [38.1K]3 years ago
8 0

Answer:

B) 112 cm²; 336 cm²

Step-by-step explanation:

The lateral area would be without the bases. In this case, the bases are the top and the bottom

Lateral Area

(2)(2.54)(8) = 40.64

(2)(2.54)(14) = 71.12

Add together and get 111.76 cm²

Surface Area

LA + Bases

<em>Bases</em>

(2)(14)(8) = 224

Add with lateral area and get 335.76 cm²

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Problem is in the attached image. Thanks in advance!
lutik1710 [3]

Answer: it will take 2.5 hours for both people to meet after person B leaves.

Step-by-step explanation:

The distance between the house of person A and his cousin's house is 234 miles.

At the point where they meet, they would have travelled 234 miles.

Person A travelled at an average speed of 44 miles per hour.

Let t represent the time spent by Person A in travelling from his house to the point where they meet.

Distance = speed × time

Distance covered by person A would be

44 × t = 44t

One and half hours later, person B leaves his house to visit person A, travelling at an average speed of 62 miles per hour. This means that total time spent by person B in travelling to the point where they meet is (t - 0.5) hours. Distance covered would be

62(t - 0.5) = 62t - 31

Since the total distance covered is 234 miles, then

44t + 62t - 31 = 234

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3 0
2 years ago
Given: AB || DE , AD bisects BE.<br> Prove: ABC = DEC using the ASA postulate.
Ket [755]

Answer:

As per ASA postulate, the two triangles are congruent.

Step-by-step explanation:

We are given two triangles:

\triangle ABC and \triangle DEC.

AD bisects BE.

AB || DE.

Let us have a look at two properties.

1. When two lines are parallel and a line intersects both of them, then <em>alternate angles </em>are equal.

i.e. AB || ED and \angle B and \angle E are alternate angles \Rightarrow \angle B = \angle E.

2. When two lines are cutting each other, angles formed at the crossing of two, are known as <em>Vertically opposite angles </em>and they are are <em>equal</em>.

\Rightarrow \angle ACB = \angle DCE

Also, it is given that <em>AD bisects BE</em>.

i.e. EC = CB

1. \angle B = \angle E

2. EC = CB

3. \angle ACB = \angle DCE

So, we can in see that in \triangle ABC and \triangle DEC, two angles are equal and side between them is also equal to each other.

Hence, proved that \triangle ABC \cong \triangle DEC.

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2 years ago
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algol13

Answer: did you get the answer??????

Step-by-step explanation:

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