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Cloud [144]
3 years ago
8

Write an equation that you can use to find the m

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
5 0
M =180 - 148-24 I THINK this shoud work
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Warren is on vacation and needs to arrange transportation. A rental car costs 60 dollars per day plus a one-time cost of 14 doll
Vlad1618 [11]

Answer:

The answer is C(x) = 60x + 14 and the answer to the second one is 7 days.

Step-by-step explanation:

C(x) =60x + 14

434 = 60x + 14

-14                -14

420 = 60x

/60      /60

7 = x

or

x = 7 days

3 0
3 years ago
Read 2 more answers
Colin invests £2350 into a savings account. The bank gives 4.2% compound
marin [14]

Answer:

Answer:

£3692

Step-by-step explanation:

A = p(1 + r/n)^nt

Where,

A = future value

P = principal = £2350

r = interest rate = 4.2% = 0.042

n = number of periods = 1(annual)

t = time = 4 years

A = p(1 + r/n)^nt

= 2350(1 + 0.042/1)^1*4

= 2350(1 + 0.042)^4

= 2350(1.042)^4

= 2350(1.5789)

= 2770.42

A = £2770.42

Total years = 10

Remaining years = 10 – 4

= 6 years

Remaining 6 years

P = £2770.42

r = 4.9% = 0.049

n = 1

t = 6

A = p(1 + r/n)^nt

= 2770.42(1 + 0.049/1)^1*6

= 2770.42(1 + 0.049)^6

= 2770.42(1.049)^6

= 2770.42(1.3325)

= 3691.59

A = £3691.59

Approximately £3692

Thank you!

5 0
3 years ago
6.23+(-12.49)-2.6<br> What's the answer?
Mila [183]
6.23+ -12.49 -2.6= 6.23+ -12.49+ -2.6
-6.26+-2.6= -8.86
4 0
3 years ago
Read 2 more answers
A teacher teaches two classes with 8 students each. Each student has a 95% chance of passing their class independent of the othe
dsp73

Answer:

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they pass, or they do not. The probability of an student passing is independent of other students, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability that all students pass in a class:

Class of 8 students, which means that n = 8

Each student has a 95% chance of passing their class independent of the other students, which means that p = 0.95

This probability is P(X = 8). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{8,8}.(0.95)^{8}.(0.05)^{0} = 0.6634

Find the probability that, in exactly one of the two classes, all 8 students pass.

Two classes means that n = 2

0.6634 probability all students pass in a class, which means that p = 0.6634.

This probability is P(X = 1). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,1}.(0.6634)^{1}.(0.3366)^{1} = 0.4466

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

3 0
3 years ago
Complete the steps to solve the inequality:<br><br> 0.2(x + 20) – 3 &gt; –7 – 6.2x
Zigmanuir [339]

answer: x > - 1.25

Step-by-step explanation:

0.2 •(x + 20)- 3> -7- 6.2x

0.2x + 1> - 7 - 6.2x

3 0
3 years ago
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