The instantaneous rate of change of the function f(x) = −4x² − 3x + 1 at the point x = -3 is 21.
<h3>What is the instantaneous rate of change of the function at the given point?</h3>
The instantaneous rate of change is simply the change in the derivative value at a specific point.
Given the data in the question;
- f(x) = −4x² − 3x + 1
- Point x = -3
To determine the instantaneous rate of change of the function, first find the derivative of the function.
f(x) = −4x² − 3x + 1
Applying sum rule, with respect to x
d/dx[ -4x² ] + d/dx[ -3x ] + d/dx[ 1 ]
[ 2 × -4x¹ ] + [ 1 × -3x⁰ ] + d/dx[ 1 ]
[ -8x ] + [ -3 ] + d/dx[ 1 ]
-8x - 3 + d/dx[ 1 ]
Differentiate using constant rule
-8x - 3 + [ 0 ]
-8x - 3
f'(x) = -8x - 3
Next, plug x = -3 into the derivative and simplify.
f'(x) = -8x - 3
f'(-3) = -8(-3) - 3
f'(-3) = 24 - 3
f'(-3) = 21
Therefore, the instantaneous rate of change of the function f(x) = −4x² − 3x + 1 at the point x = -3 is 21.
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Answer:
150.8
Step-by-step explanation:
Hopefully this'll help you out!
Answer:
The minimum sample needed to provide a margin of error of 3 or less is 52.
Step-by-step explanation:
The confidence interval for population mean (<em>μ</em>) is:
The margin of error is:
<u>Given:</u>
MOE = 3
<em>σ </em>= 11
The critical value for 95% confidence interval is:
**Use the <em>z</em>-table for critical values.
Compute the sample size (<em>n</em>) as follows:
Thus, the minimum sample needed to provide a margin of error of 3 or less is 52.
Answer:
1 1/8
Step-by-step explanation:
First, Make the first fraction into a new one with an equal denominator. (3/4 x2= 6/8)
Then, subtract the whole numbers (2-1=1) and the fractions (6/8-5/8= 1/8)
Lastly, add your two differences together and you get 1 1/8.
The data are skewed and there is an outlier statement first is correct.
<h3>What is the box and whisker plot?</h3>
A box and whisker plot is a method of abstracting a set of data that is approximated using an interval scale. It's also known as a box plot. These are primarily used to interpret data.
We have data on the box plot.
Because the dots decrease as the number line grows, the depicted dot plot is skewed right.
The graph's "tail" is pushed toward greater positive numbers. As a result, the mean is pushed towards the graph's tail and is higher than the median.
Thus, the data are skewed and there is an outlier statement first is correct.
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