The problem is -2a - 5 > 3
we have - 2a>3+5
or - 2a>8 and now we divide by - 2
and a< 8/(-2) or a< -4
That means you have to choose D- the last line
I believe it's<span> 8cos(x)⁸ - 16cos(x)⁶ + 10cos(x)⁴ - 2cos(x)².
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![8cosx^8 - 16cosx^6+10cosx^4-2cosx^2](https://tex.z-dn.net/?f=8cosx%5E8%20-%2016cosx%5E6%2B10cosx%5E4-2cosx%5E2)
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Alternately, you can write [</span><span><span>1 / (tan(2x) - cot(2x))] + [cos(8x) / (tan(2x) - cot(2x))].
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![\dfrac{1}{tan(2x)-cot(2x)}+ \dfrac{cos(8x)}{tan(2x)-cot(2x)}](https://tex.z-dn.net/?f=%20%5Cdfrac%7B1%7D%7Btan%282x%29-cot%282x%29%7D%2B%20%5Cdfrac%7Bcos%288x%29%7D%7Btan%282x%29-cot%282x%29%7D%20%20)
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1) 108
2) 72
3) 36
4) 72
5) 72
6) 144
7) 72
8) 72
9) 108
10) 108
I hope this helped
Answer:
Acute
Step-by-step explanation:
An acute triangle has three angles that each measure less than 90 degrees.
If you put 145 divided by 8 the remainder on a calculator would come out as a decimal