Answer:
All answers other than {7, 11, 15, 19}
Step-by-step explanation:
If we have a Set A, it is a subset of Set B if every element in A is also in B. Set A is a proper subset of Set B if it is a subset of Set B but not equal to Set B.
Using the above information, we know that the proper subset of {7, 11, 15, 19} cannot be itself, so we can rule out the second option.
All of the other options are sets where every element of that set is also an element of {7, 11, 15, 19}. The 3rd option is an empty set, which is a proper subset of any set other than itself, so it is a proper subset of {7, 11, 15, 19}.
Therefore, all of the options except for {7, 11, 15, 19} are valid.
Answer: the fourth choice: <span>No, the addition symbol was dropped in the second expression
Justification:
1) The right operation is: </span><span>(4.5m + 7/8) - 9 </span><span>= 4.5m + (7/8 - 9), this is you have to keep the + operator, since you are just grouping the terms in an alternate form.
2) Droping the + operator leads incorrectly to the multiplication of the first term, 4.5m to the terms in parenthesis, instead to the addition, which is what corresponds.
</span>
C
-28 is his debt and adding or paying +7 every week
The answer is C) all real numbers greater than or equal to one.
Hope this helps!
Answer:
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