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anastassius [24]
3 years ago
14

A car drove 10/45 miles in 0.4 hours. How fast was the car traveling in miles per hour?

Mathematics
1 answer:
BARSIC [14]3 years ago
7 0

Answer:

1.2 hours equal to 30mph

Step-by-step explanation:

Pls mark brainliest

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1   -   12
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What is the equation of the line of best fit that Frank drew?<br> 
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its a

Step-by-step explanation:

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Here are two squares A and B. The length of the side A is 50% of the length of the side square B. Express the area of the shaded
Darya [45]

Answer:

12.5%

Step-by-step Explanation:

==>Given:

Square A side length = 50% Square B side length

Area of Square A that is shaded = ½ of the area of Square B

==>Required:

Area of shaded region of Square A as a % of Area of Square B

==>Solution:

Let "b" be the side length of Square B

Let "a" be the side length of Square A

Since we are told that the side length of Square A (a) = 50% of side length of Square B (b), thus we have,

a = ½b

==>Let's find the area of Square A and Square B:

Area of a square = s², where s = side length

Area of Square A = (½b)² = b²/4

Area of Square B = b²

==>Let's find the area of the shaded region of the Square A = ½ of area of Square A.

Thus,

Area of shaded region of Square A = ½*(b²/4) = b²/8

==>Let's express the area of the shaded portion of square A as a percentage of are of Square B:

Thus, Area of shaded portion of Square A ÷ Area of Square B × 100%

= \frac{\frac{b^{2} }{8}  }{b^{2} } * 100

= \frac{b^{2} }{8} * \frac{1}{b^{2} } * 100

= \frac{b^{2}*1 }{8*b^{2} } * 100

= \frac{b^{2} }{8*b^{2} } * 100

= \frac{1}{8} * 100 = 12.5

The area of the shaded region of Square A is 12.5% of the area of Square B.

8 0
3 years ago
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