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Aleksandr-060686 [28]
4 years ago
9

Which expression is equivalent to 46 ⋅ 4−8?

Mathematics
1 answer:
Mazyrski [523]4 years ago
7 0

Let's do 46 * 4 - 8 first to get 176.

The first 2 will be less than 1\4 (powering a fraction reduces it) so they are wrong
42 and 414 aren't equal to 176 soooo.....

None of the above?

Hope this helps!

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A mixture of 30 pounds of candy sells for $1.10 a pound. The mixture consists of chocolates worth $1.50 a pound and chocolates w
Allushta [10]

Answer: Option 'B' is correct.

Step-by-step explanation:

Number of pounds of candy = 30

Cost per pound = $1.10

Total amount would be

30\times 1.10\\\\=33

Let the number of pound that sold at $1.50 per pound be 'x'.

Let the number of pound that sold at 90 cents per pound be '30-x.

According to question, we get that

1.5x+0.90(30-x)=33\\\\1.5x+27-0.90x=33\\\\1.5x-0.9x=33-27\\\\0.6x=6\\\\x=\dfrac{6}{0.6}=10

Hence, there are 10 pounds of chocolates worth $1.50 per pound.

Therefore, Option 'B' is correct.

8 0
3 years ago
Solve the exponential equation<br> 9^2x = 27
krek1111 [17]
27 = 9^(3/2) 
.
so x = 4/3
4 0
4 years ago
Read 2 more answers
Will mark brainlist please be neat
34kurt

10+3+10+6+7

Add them = 36.

P= 36 ft

hope it helped

4 0
3 years ago
Read 2 more answers
You invested $6,500 in an account that pays 6 percent simple interest. how much more could you have earned over a 10-year period
Klio2033 [76]
6500(1.06^10)-10(6500*.06)+6500=$1240.51

6 0
3 years ago
Sphere A and Sphere B , are similar. The volumes of A and B, are 17 and 136 cubic centimetres, respectively. The diameter of B ,
xxMikexx [17]

Answer:

3

Step-by-step explanation:

Given: Sphere A and Sphere B are similar.

The volumes of A and B are 17 cm^3and 136

The diameter of B is 6 cm.

To find: diameter of A

Solution:

Let R denotes radius of sphere A and r denotes radius of sphere B.

Radius of sphere A= R

Diameter of sphere B = 6 cm

So, radius of sphere B (r) = \frac{6}{2}=3\,\,cm

Volume of sphere is \frac{4}{3}\pi(radius)^3

Volume of sphere A = \frac{4}{3}\pi(R)^3

\frac{\frac{4}{3}\pi R^3}{\frac{4}{3}\pi r^3}=\frac{17}{136}=\frac{1}{8}\\\frac{R^3}{r^3}=\frac{1}{8}\\\frac{R}{r}=\frac{1}{2}\\r=2R

Put r = 3 cm

3=2R\\R=\frac{3}{2}=1.5\,\,cm

Diameter of sphere A = 2 × Diameter

= 2 × 1.5

=3 cm

6 0
3 years ago
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