1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
OLga [1]
3 years ago
7

1. Isaac goes to an amusement park where tickets for the rides cost $10 per sheet and tickets for the shows cost $15 each.

Mathematics
1 answer:
Degger [83]3 years ago
7 0
The answers I have gotten are
A- x+y= $25
B- $95
You might be interested in
One type of insect is 0.0052 meters long. what is this length in scientific notation?
pochemuha
Your answer would be:
5.2*10^(-3)

hope this helps!
happy thanksgiving
4 0
3 years ago
Read 2 more answers
Find dy/dx by implicit differentiation for ysin(y) = xcos(x)
tatyana61 [14]

Answer:

\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}

Step-by-step explanation:

So we have:

y\sin(y)=x\cos(x)

And we want to find dy/dx.

So, let's take the derivative of both sides with respect to x:

\frac{d}{dx}[y\sin(y)]=\frac{d}{dx}[x\cos(x)]

Let's do each side individually.

Left Side:

We have:

\frac{d}{dx}[y\sin(y)]

We can use the product rule:

(uv)'=u'v+uv'

So, our derivative is:

=\frac{d}{dx}[y]\sin(y)+y\frac{d}{dx}[\sin(y)]

We must implicitly differentiate for y. This gives us:

=\frac{dy}{dx}\sin(y)+y\frac{d}{dx}[\sin(y)]

For the sin(y), we need to use the chain rule:

u(v(x))'=u'(v(x))\cdot v'(x)

Our u(x) is sin(x) and our v(x) is y. So, u'(x) is cos(x) and v'(x) is dy/dx.

So, our derivative is:

=\frac{dy}{dx}\sin(y)+y(\cos(y)\cdot\frac{dy}{dx}})

Simplify:

=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}

And we are done for the right.

Right Side:

We have:

\frac{d}{dx}[x\cos(x)]

This will be significantly easier since it's just x like normal.

Again, let's use the product rule:

=\frac{d}{dx}[x]\cos(x)+x\frac{d}{dx}[\cos(x)]

Differentiate:

=\cos(x)-x\sin(x)

So, our entire equation is:

=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}=\cos(x)-x\sin(x)

To find our derivative, we need to solve for dy/dx. So, let's factor out a dy/dx from the left. This yields:

\frac{dy}{dx}(\sin(y)+y\cos(y))=\cos(x)-x\sin(x)

Finally, divide everything by the expression inside the parentheses to obtain our derivative:

\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}

And we're done!

5 0
2 years ago
The perimeter of a rectangular painting is 326 cm. if the width of the painting is 74 cm, what is the length?
True [87]
Perimeter (P) = 326 cm

Width (w) = 74 cm

Length (l) = ?

We know,

P = 2* (l + w)

326 = 2 (l + 74)

l + 74 = 163

l = 89 

Hence, length is 89 cm.
7 0
3 years ago
Answers for the 2 boxes please ​
pochemuha
(-3,-6) this is the answer you can also double check by plugging it into a calculator
6 0
2 years ago
Factor the expression by finding the GCF.
Deffense [45]

Answer:

4m(4m-3)

Step-by-step explanation:

Factor 4m out of the statement because 4 is a factor of both 16 and -12, and m is a factor in m^2 and m.

8 0
2 years ago
Other questions:
  • Can you help me solve this inequality?
    15·1 answer
  • Simplify the expression?
    12·1 answer
  • PLEASE HELP ME SOLVE!!!!
    11·1 answer
  • A local college student will be randomly selected to attend a leadership conference in Washington, D.C. There are 2110 local col
    11·1 answer
  • Select the two binomials that are factors of this trinomial.
    15·1 answer
  • What is the measure (in radians) of central angle in<br> the circle below?<br> 4 cm<br> 6 cm
    8·1 answer
  • Melanie moved to Toledo on September 14 and returned home for a visit fifteen months later. When did she return home?
    15·2 answers
  • Where do the slope and y-intercept show up in the tables and graphs?
    12·2 answers
  • Triangle PQR is an isosceles triangle with the coordinates P(2, 3), Q(5, 10), and R(8,3).
    7·1 answer
  • BUILD PERSEVERANCE Find the values of x and y. List your answers in ascending order.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!