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DaniilM [7]
3 years ago
6

A mixture of 30 pounds of candy sells for $1.10 a pound. The mixture consists of chocolates worth $1.50 a pound and chocolates w

orth 90¢ a pound. How many pounds of the $1.50 chocolate were used to make the mixture?A. 15B. 10C. 12
Mathematics
1 answer:
Allushta [10]3 years ago
8 0

Answer: Option 'B' is correct.

Step-by-step explanation:

Number of pounds of candy = 30

Cost per pound = $1.10

Total amount would be

30\times 1.10\\\\=33

Let the number of pound that sold at $1.50 per pound be 'x'.

Let the number of pound that sold at 90 cents per pound be '30-x.

According to question, we get that

1.5x+0.90(30-x)=33\\\\1.5x+27-0.90x=33\\\\1.5x-0.9x=33-27\\\\0.6x=6\\\\x=\dfrac{6}{0.6}=10

Hence, there are 10 pounds of chocolates worth $1.50 per pound.

Therefore, Option 'B' is correct.

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3x-2y&lt;10 <br> in a graph<br> graphing linear equalities
faltersainse [42]

Answer:

I hope it will help you!

Step-by-step explanation:

5 0
3 years ago
PLEASE HELP!
Mariana [72]
-----------------------------------------------
Information Given:
-----------------------------------------------
ON = 7x - 9
LM = 6x + 4
MN = x - 7
OL = 2y - 7

-----------------------------------------------
Since it is a parallelogram:
-----------------------------------------------
ON = LM and
MN = OL

-----------------------------------------------
ON = LM:
-----------------------------------------------
7x - 9 = 6x + 4

-----------------------------------------------
Subtract 6x from both sides:
-----------------------------------------------
x - 9 = 4

-----------------------------------------------
Add 9 to both sides:
-----------------------------------------------
x = 13

-----------------------------------------------
MN = OL:
-----------------------------------------------
x - 7 = 2y - 7

-----------------------------------------------
Sub x = 13:
-----------------------------------------------
13 - 7 = 2y - 7

-----------------------------------------------
Simplify:
-----------------------------------------------
6 = 2y - 7

-----------------------------------------------
Add 7 on both sides:
-----------------------------------------------
13 = 2y

-----------------------------------------------
Divide by 2:
-----------------------------------------------
y = 13/2

-----------------------------------------------
Answer: x = 13, y = 13/2 (Answer D)
-----------------------------------------------


6 0
3 years ago
Suppose a die is tossed 5 times. what is the probability of getting exactly 2 fours?
Tasya [4]

Answer:

the probability of getting exactly 2 fours is 0.16

Step-by-step explanation:

The probability of obtaining a number that is four = ¹/₆

The probability of obtaining a non 4 number = 1 - ¹/₆ = ⁵/₆

The number of ways 2 fours can be arrange in five numbers = ⁵C₂ = 10 ways

If the die is tossed five times, the probability of the events is calculated as;

P = 10 x (¹/₆)² x (⁵/₆)³

P = 10 x (¹/₃₆) x  (¹²⁵/₂₁₆)

P = 10 x 0.02778 x 0.5787

P = 0.16

Therefore, the probability of getting exactly 2 fours is 0.16

7 0
2 years ago
What does gemdas and pemdas stands for?
DanielleElmas [232]

Answer:

For pemdas

P Parentheses

E Exponents

M Multiplication

D Division

A Addition

S Subtraction

And for gemdas

G Grouping

E Exponents

M Multiplication

D Division

A Addition

S Subtraction

8 0
3 years ago
Read 2 more answers
5 4/8 + 1 3/8 =<br> 1. 33/8<br> 2. 55/8<br> 3. 6 7/16
Dovator [93]

Answer: 2. 55/8

Step-by-step explanation: Add the whole numbers first (5+1 = 6), then add the fractions (4/8 + 3/8 = 7/8). Now we have 6 7/8 and since they want the answer in fraction form we will multiply the 6 and the 8 (6x8=48) and then add the 7 to the 48 (7+48 =55) and we leave our answer over the denominator which is 8. This leaves us with the final answer of 55/8

4 0
1 year ago
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