What goes in goes out. This means none of the current is lost. So if 0.7amps+0.68amps+0.47amps = 1.85 amps comes in, then 1.85 amps goes out. So far we have 0.8 amps+0.55 amps going out= 1.35 amps. This means we need an additional 1.85-1.35amps going out= 0.5 amps for the third outgoing current. Cheers!
Answer:
7. one triangle
8. two triangles
Step-by-step explanation:
When you are given two sides and one of the opposite angles, you can make a determination as follows:
- If the given angle is <em>opposite the longest given side</em>, there is one solution.
- If the given angle is <em>opposite the shortest given side</em>, there may be 0, 1, or 2 solutions.
For the latter case, the possibilities for sides b, c, and angle C are ...
C > 90° . . . . . . . . no solution
(b/c)sin(C) > 1 . . . no solution
(b/c)sin(C) = 1 . . . 1 solution
(b/c)sin(C) < 1 . . . 2 solutions
(The expression (b/c)sin(C) gives sin(B), so the value must lie within the range of the sine function in order for there to be any solution.)
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7. The given angle is opposite the <em>longest</em> given side. There is one solution.
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8. The given angle is opposite the <em>shortest</em> given side, so we compute
(b/c)sin(C) = (34/28)sin(20°) ≈ 0.41
This is less than 1, so there are two solutions.
Answer:
x = 1
Step-by-step explanation:
2(4x) = 8
2(4x) = 2 * 4x
2 * 4x = 8x
8x = 8
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8 8
x = 1
Answer:
1.13
Step-by-step explanation:
Bc and ef are congruent so that means
4x-7 =2x+3 subtract 2x from both sides
-2x -2x
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2x-7 = 3 add seven to both sides
+7 +7
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2x = 10 divide both sides by 2
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2 2
x=5 replace x with 5
4(5) -7= 13
2(5) +3=13
both bc and ef equal 13