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Blababa [14]
3 years ago
9

I need help this is due tomorrow and I have to write an essay so please help!!!

Mathematics
1 answer:
HACTEHA [7]3 years ago
4 0
2.) 6k - 9
*can't see #3*
4.) -9p + 17
5.) -15b^2 - 1b + 6c
6.) -4j
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Please help me..............................
myrzilka [38]

Answer:

y = 12

Step-by-step explanation:

∵ m∠ABC = 40

∵ BD ray is the bisector of ∠ABC

∴ m∠ABD = m∠CBD = 20

In 2 Δ BAD and BCD:

∵ m∠BAD = m∠BCD = 90°

∵ m∠ABD = m∠CBD = 20°

∵ BD is a common side in the two triangles

∴ ΔABD congruent to ΔCBD⇒(AAS)

∴ AD = CD

∴ 3y + 6 = 5y - 18

∴ 5y - 3y = 6 + 18

∴ 2y = 24

∴ y = 24/2 = 12

6 0
3 years ago
The number from the set will make the equation x+4=7.8 true
nikklg [1K]

Answer:

X=3.8 (I may be wrong sry)

Step-by-step explanation:

6 0
3 years ago
Jenna has a piece of paper that is 84 square inches in area. it is 10 1/2 inches long. what is the length of the piece of paper
Ronch [10]
I hope this helps you

6 0
3 years ago
3 On a coordinate grid, the location of a lighthouse is at L, and the location of a buoy is at B. At noon, a ship is at the midp
Zarrin [17]

Answer:

(\frac{1}{2}, 2)

Step-by-step explanation:

Using the midpoint formula, M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}), we can find the coordinates that represents the position of the ship at noon.

Let L(-4, 7) = (x_1, y_1) (given on the coordinate plane)

B(5, -3) = (x_2, y_2) (given also)

Plug in the values into the formula and solve as follows:

M(\frac{-4 + 5}{2}, \frac{7 +(-3)}{2})

M(\frac{1}{2}, \frac{7 - 3}{2})

M(\frac{1}{2}, \frac{4}{2})

M(\frac{1}{2}, 2)

Position of the ship at noon is best represented at (\frac{1}{2}, 2)

5 0
3 years ago
Which inequality is shown in the graph?
sergij07 [2.7K]

Answer:

The answer to your question is: letter C

Step-by-step explanation:

Data

Find the Parabola's equation and express the equation as an inequality.

Vertex = (0, -5)

Equation

                               (x- h) ² = 4p(y - k)

                               x² = y + 5

                              y = x² - 5

But, we need the area upper the parabola, then

                              y ≥ x² - 5

5 0
3 years ago
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