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3 years ago

Help me, please!! Estoy desesperada y no hablo inglês!! Help

Mathematics

2 answers:

Aleksandr-060686 [28]3 years ago

8 0

$D:x>0\\
\log x+\log x^2+\log x^3=-6\\
\log (x\cdot x^2\cdot x^3)=\log 10^{-6}\\
x^6=10^{-6}\\
x^6=\left(\frac{1}{10}\right)^6\\ \boxed{x=\frac{1}{10}}$

goblinko [34]3 years ago

7 0

Log x^n = nLog x
log x + log x^2 + log x^3
Log x + 2 log x +3 log x = -6
6 log x = -6
Log x = -1
X=10^-1 = 1/10
Respuesta final
X=1/10

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