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DerKrebs [107]
3 years ago
6

Help me, please!! Estoy desesperada y no hablo inglês!! Help

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
8 0
D:x>0\\
\log x+\log x^2+\log x^3=-6\\
\log (x\cdot x^2\cdot x^3)=\log 10^{-6}\\
x^6=10^{-6}\\
x^6=\left(\frac{1}{10}\right)^6\\ \boxed{x=\frac{1}{10}}
goblinko [34]3 years ago
7 0
Log x^n = nLog x
log x + log x^2 + log x^3
Log x + 2 log x +3 log x = -6
6 log x = -6
Log x = -1
X=10^-1 = 1/10
Respuesta final
X=1/10
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Samantha and Luis are attempting to determine the average number of library books that seventh-grade students check out at one t
postnew [5]

Answer:

A

Step-by-step explanation:

Luis because the sample is taken from the population of all seventh graders.

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3 years ago
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Six friends each use a $2.00 off coupon to buy themselves a movie ticket. They spend a total of 42. What is the price of one mov
attashe74 [19]

Answer:

5

Step-by-step explanation:

you would do 42 divided by 7 which is 6 then subtract 2 from 7 and you would get 5

5 0
2 years ago
Write each mixed number as a percent 9 3/4
statuscvo [17]
The answer of 9 3/4 as a percent is
9 (900%) plus 3/4 (75%) which equals 975%
4 0
3 years ago
Sort each equation according to whether it has one solution, infinitely many solutions, or no solution.
Sedaia [141]

Answer:

Equations with one solution: -2(x-3) = 2x-6

Equations with no solution:

6(x+5) = 6x+11\\5(x-2) = 5x-7

Equations with infinite many solutions: -3(x-4) = -3x+12

Step-by-step explanation:

We will solve each equation to see if it has one solution, no solution or infinite many solutions.

An equation where the value of variable can be found has one solution.

An equation with no solution has both sides different.

An equation with infinite solution will have both sides equal after solution(number)

So,

<u>Equation 1:</u>

5(x-2) = 5x-7

5(x-2) = 5x-7\\5x-10 = 5x-7\\5x-5x = -7+10\\0 = 3

As both sides are not equal, equation has no solution.

<u>Equation 2:</u>

-3(x-4) = -3x+12\\-3x+12 = -3x+12\\-3x+3x = -12+12\\0=0\\

As both sides are equal the equation has infinite many solutions.

<u>Equation 3:</u>

-2(x-3) = 2x-6\\-2x+6 = 2x-6\\-2x-2x = -6-6\\-4x = -12\\\frac{-4x}{-4} = \frac{-12}{-4}\\x = 3

As x=3, the equation has only one solution.

<u>Equation 4:</u>

6(x+5) = 6x+11\\6x+30 = 6x+11\\6x-6x+30 = 11\\30 =11

The equation has no solution.

Hence,

Equations with one solution: -2(x-3) = 2x-6

Equations with no solution:

6(x+5) = 6x+11\\5(x-2) = 5x-7

Equations with infinite many solutions: -3(x-4) = -3x+12

6 0
2 years ago
Help and explain ///////////////////////////
Ilia_Sergeevich [38]

Hello,

First, you must understand that

(f-g)(x) means f(x)-g(x) it is the difference of two functions :

f(x)=2x+4 and g(x)=3x-7

f(5)=2*5+4=10+4=14

g(5)=3*5-7=15-7=8

So, (f-g)(5)= f(5)-g(5)=14-8<u>=6</u>

Answer A: none of the choices are correct.

An other way to do it:

(f-g)(x)=f(x)-g(x)=2x+4-(3x-7)= 2x-3x+4+7=-x+11

if x= 5 then (f-g)(5)=-5+11<u>=6</u>

4 0
2 years ago
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