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Lyrx [107]
3 years ago
13

If f(x) = │(x² – 50)│, what is the value of f(-5) ?

Mathematics
2 answers:
Liula [17]3 years ago
5 0
f(x)=|(x^2-50)|\\\\f(-5)=|(-5)^2-50|=|25-50|=|-25|=25\\\\\\|a|=  \left\{\begin{array}{ccc}a&for&a\geq0\\-a&for&a < 0\end{array}\right\\\\|-3|=3;\ |5|=5;\ |0|=0;\ |-12|=12
fenix001 [56]3 years ago
3 0

Answer:

25

Step-by-step explanation:

f(x) = [ (x^2 - 50 ) } ,

f( - 5) = [ (-5)^2 - 50) ]

f( - 5) = [ 25 - 50]

f( - 5) = [ -25 ]

f(-5) = 25

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The vertical asympototes of f(x) are  at x = -6 and x = 6

Step-by-step explanation:

To find the vertical asymptote(s) of a rational function,

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∵ f(x)=\frac{4x^{2}+3x+6}{x^{2}-36}

- Equate the denominator x² - 36 by 0

∵ x² - 36 = 0

- Add 36 to both sides

∴ x² = 36

- Take √ for both sides

∴ x = ± 6

∴ There are vertical asymptotes at x = -6 and x = 6

The vertical asympototes of f(x) are  at x = -6 and x = 6

Learn more:

You can learn more about the asymptotes in brainly.com/question/6459599

#LearnwithBrainly

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Answer:

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Step-by-step explanation:

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zzz [600]

Answer:

B.

Step-by-step explanation:

To simplify something that looks like \frac{\text{whatever}}{\sqrt{a}-\sqrt{b}} you would multiply the top and bottom by the conjugate of the bottom. So you multiply the top and bottom for this problem I just made by:

\sqrt{a}+\sqrt{b}.

If you had  \frac{\text{whatever}}{\sqrt{a}+\sqrt{b}}, then you would multiply top and bottom the conjugate of \sqrt{a}+\sqrt{b} which is \sqrt{a}-\sqrt{b}.

The conjugate of a+b is a-b.

These have a term for it because when you multiply them something special happens.  The middle terms cancel so you only have to really multiply the first terms and the last terms.

Let's see:

(a+b)(a-b)

I'm going to use foil:

First:  a(a)=a^2

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Inner:  b(a)=ab

Last:    b(-b)=-b^2

--------------------------Adding.

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See -ab+ab canceled so all you had to do was the "first" and "last" of foil.

This would get rid of square roots if a and b had them because they are being squared.

Anyways the conjugate of \sqrt{17}-\sqrt{2} is

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8 0
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A soup can will have a radius of 4 cm and a
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Answer:

<h3>            It's about 365 cm²</h3>

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