The given values are:
p = 22% = 0.22
Zc = 1.645 at 90% confidence level.
margin of error, E = 0.04
The formula we can use here is:
E = sqrt(pq/n) * Zc
0.04 = sqrt(0.22*(1-0.22)/n)*1.645
n = (0.22*(1-0.22))*(1.645/0.04)^2
n = 290.22
hence minimum sample size = 290
What model? also it would be 1/2 and 1/3
He spent $9.50 in total. To find this answer, you write the equation 2(9.95) + 3(1.20). You would distribute getting 5.90 + 3.60= $9.50.
Answer: 41
Step-by-step explanation:
