Consider the scatter plot.

Mathematics

1 answer:

BARSIC [14]3 years ago

7 0

No association is your answer my friend

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Find the slope of the line that passes through each pair of points. (-3, 1 )and (-17, 2)

ASHA 777 [7]

Answer:

1/-14 or 1 over - 14

Step-by-step explanation:

The equation you need is: y2-y1 over x2-x1

So if you plug it in it becomes 2-1 over -17 -(-3) so 2 - 1 is 1 that's the easy part, 17 - (-3) is the hard part because you can't minus a negative. So it becomes -17+3 which is still -14 because you take the sign of the bigger number. Sorry if it's hard to understand :(

3 0

3 years ago

V(x)=x^2-25

Whitepunk [10]

Answer:

-∞ < x < -5 ∪ -5 < x < -3/2 ∪ -3/2 < x < ∞

Step-by-step explanation:

The domain of any polynomial is "all real numbers." The domain of any rational function excludes any values of the variable that result in the denominator being 0. The function is "undefined" there.

$v(x)=\dfrac{x^2-25}{2x^2+13x+15}=\dfrac{(x+5)(x-5)}{(x+5)(2x+3)}\qquad x\notin \{-5,-\dfrac{3}{2}\}$

The values x=-5 and x=-3/2 make the denominator of v(x) become 0, so those values are excluded from the domain of v(x). The function is "undefined" when its denominator is zero.

-∞ < x < -5 ∪ -5 < x < -3/2 ∪ -3/2 < x < ∞

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<em>Additional comment</em>

The numerator and denominator factors (x+5) cancel each other, so there is no vertical asymptote at x=-5. Rather, the function has a "hole" there, where it is undefined. The limit as the function approaches x=-5 from either direction is v(x) = 10/7.