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Kisachek [45]
3 years ago
8

) suppose an operating system allocates time slices in 10 millisecond (1/1000 second) units and the time required for a context

switch is negligible. how many processes can obtain a time slice in one second?
Mathematics
1 answer:
victus00 [196]3 years ago
3 0

(1 second)*(1 process)/(10/1000 second) = 1000/10 processes = 100 processes

100 processes can obtain a time slice in 1 second.

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How many groups of ten are there in 230?
Artyom0805 [142]

Answer:

I am pretty sure the answer is 23

Step-by-step explanation:

The answer is 23 because if you multiply 23 by 10 you get 230 which is the same if you divided 230 by 10 and you get 23.

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The sum of this 4 digit even number's thousands and ones digit is 10
Vladimir [108]
Even
means ends with 0,2,4,6,8

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it can be
8xx2
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What is 4 dogs with 12 legs
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5 0
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Solve for x: −3x + 3 &lt; 6<br><br> x &gt; −1<br> x &lt; −1<br> x &lt; −3<br> x &gt; −3
Misha Larkins [42]

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Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Iron Man Training While training for an iron man competition, Tony bikes for 60 miles and runs for 15 miles. If his bikes speed
ivolga24 [154]

Answer:

<u>Tony biked 1 hour 40 minutes and run 3 hours 20 minutes.</u>

Step-by-step explanation:

How long did Tony speed on his bike?

Let s to be Tony's running speed, then 8s is Tony's biking speed

Let's recall that Time = Distance/Speed

Bike time + Running time = 5 hrs

Replacing with the real values, we have:

60/8s + 15/s = 5

8s as Lowest Common Denominator

60 + 8 * 15 = 5 * 8s

60 + 120 = 40s

-40s = -180

s = -180-40

s = 4.5 ⇒ 8s = 36

Tony run at 4.5 mph and biked at 36 mph

Now, we can calculate the time, this way:

Bike time = Bike distance/Bike speed

Replacing with the real values, we have:

Bike time = 60/36

Bike time = 5/3 (Dividing by 12)

5/3 hours * 60 = 100 minutes or 1 hour 40 minutes

Running time = 5 hours - 1 hour 40 minutes = 3 hours 20 minutes

<u>Tony biked 1 hour 40 minutes and run 3 hours 20 minutes.</u>

4 0
3 years ago
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