Ask question

Ask question

All categories

3 years ago

8

) suppose an operating system allocates time slices in 10 millisecond (1/1000 second) units and the time required for a context

switch is negligible. how many processes can obtain a time slice in one second?

1 answer:

victus00 [196]3 years ago

3 0

(1 second)*(1 process)/(10/1000 second) = 1000/10 processes = 100 processes

100 processes can obtain a time slice in 1 second.

You might be interested in

Multiply 9/4 x 14<br><br> -23/4<br> -28<br> -63/2

Tatiana [17]

Answer:

<h2> $\frac{63}{2}$ </h2>

Step-by-step explanation:

$14 = \frac{14}{1}$

$\frac{9}{4} \times \frac{14}{1} = \frac{126}{4} = \frac{63}{2}$

6 0

3 years ago

Read 2 more answers

If 23 people shake each others hands once how many hands are shook in all

AURORKA [14]

This is the number of combinations of 2 from 23
23C2 = 23! / 2! 21!

A quick way to do this is 23*22 / 2 = 253

7 0

3 years ago

How many times does six go into forty-eight?

Marizza181 [45]

6 x 8 = 48, the answer is 8, just divide 48 by 6.

3 0

3 years ago

Solve the triangle A = 2 B = 9 C =8

VARVARA [1.3K]

Answer:

$\begin{gathered} A=\text{ 12}\degree \\ B=\text{ 114}\degree \\ C=54\degree \end{gathered}$

Step-by-step explanation:

To calculate the angles of the given triangle, we can use the law of cosines:

$\begin{gathered} \cos (C)=\frac{a^2+b^2-c^2}{2ab} \\ \cos (A)=\frac{b^2+c^2-a^2}{2bc} \\ \cos (B)=\frac{c^2+a^2-b^2}{2ca} \end{gathered}$

Then, given the sides a=2, b=9, and c=8.

$\begin{gathered} \cos (A)=\frac{9^2+8^2-2^2}{2\cdot9\cdot8} \\ \cos (A)=\frac{141}{144} \\ A=\cos ^{-1}(\frac{141}{144}) \\ A=11.7 \\ \text{ Rounding to the nearest degree:} \\ A=12º \end{gathered}$

For B:

$\begin{gathered} \cos (B)=\frac{8^2+2^2-9^2}{2\cdot8\cdot2} \\ \cos (B)=\frac{13}{32} \\ B=\cos ^{-1}(\frac{13}{32}) \\ B=113.9\degree \\ \text{Rounding:} \\ B=114\degree \end{gathered}$ $\begin{gathered} \cos (C)=\frac{2^2+9^2-8^2}{2\cdot2\cdot9} \\ \cos (C)=\frac{21}{36} \\ C=\cos ^{-1}(\frac{21}{36}) \\ C=54.3 \\ \text{Rounding:} \\ C=\text{ 54}\degree \end{gathered}$

3 0

1 year ago

I'm testing something, so you can just take the points if you want I don't care.

SVEN [57.7K]

Answer:

...Okay thank you!

Step-by-step explanation:

...... :)

3 0

2 years ago

Read 2 more answers