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3 years ago

8

) suppose an operating system allocates time slices in 10 millisecond (1/1000 second) units and the time required for a context

switch is negligible. how many processes can obtain a time slice in one second?

1 answer:

victus00 [196]3 years ago

3 0

(1 second)*(1 process)/(10/1000 second) = 1000/10 processes = 100 processes

100 processes can obtain a time slice in 1 second.

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How do I express the area of a square as a monomial

antiseptic1488 [7]

Well, the Area of a Rectangle = Length x Width, and a square is a rectangle with all equal sides, which means Length = Width, so the Area of a Square = Length x Length = Length^2, which you can write as x^2. The Area of a Square = x^2, where x is the length of one side of the square.

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3 years ago

Find an equation in slope-intercept form for the perpendicular bisector of the segment with endpoints H(–3, 2) and K(7, –5).

MA_775_DIABLO [31]

Y=7/10x+(-4)
The slope of HK is -10/7, so a perpendicular slope is 7/10
The y intercept of a line with m=7/10 going through the midpoint of HK has a y intercept of -4, therefore: y=7/10x+(-4)

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4 years ago

There are 10 yellow, 6 green, 9 orange, and 5 red cards in a stack of cards turned facedown. Once a card is selected, it is not

Allushta [10]

Answer:

19/30

Step-by-step explanation:

add all of them together then subtract the red and green

10+6+9+5= 30

red and green= 5+6=11

30-11=19

19/30

3 0

3 years ago

A cylinder has a volume of 288pie cubic meters and a height of 9 meters. What is the area of the base?

Butoxors [25]

  V = πr²h
  288 = 3.14(r²)(9)
  288 = 3.14(9r²)
  288 = 28.26r²
28.26 28.26
10.19 ≈ r²
  3.19 ≈ r

B = πr²
B = 3.14(3.19)²
B = 3.14(10.19)
B = 31.9966

7 0

3 years ago

Read 2 more answers

ANSWER ASAP PLZ!!

Vikentia [17]

$\text{If is}\\\\\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2\end{array}$

Answer:

$\large\boxed{\left(-\dfrac{344}{69},\ -\dfrac{38}{3}\right)}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2&\text{multiply both sides by (-0.3)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}0.2-0.3y=4\\-0.69x+0.3y=-0.36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-0.69x+0.2=3.64\qquad\text{subtract 0.2 from both sides}\\.\qquad-0.69x=3.44\qquad\text{divide both sides by (-0.69)}\\.\qquad x=-\dfrac{3.44\cdot100}{0.69\cdot100}\\.\qquad \boxed{x=-\dfrac{344}{69}}\\\\\text{Calculate the value of y from first equation:}$

$0.2-0.3y=4\qquad\text{subtract 0.2 from both sides}\\-0.3y=3.8\qquad\text{divide both sides by (-0.3)}\\y=-\dfrac{3.8\cdot10}{0.3\cdot10}\\\boxed{y=-\dfrac{38}{3}}$

--------------------------------------------------------------------------

$\text{If is}\\\\\left\{\begin{array}{ccc}0,2x-0,3y=4\\2.3x-y=1.2\end{array}\right$

Answer:

$\large\boxed{\left(-\dfrac{52}{7},\ -\dfrac{128}{7}\right)}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}0.2x-0.3y=4&\text{multiply both sides by 10}\\2.3x-y=1.2&\text{multiply both sides by 10}\end{array}\right\\\\\left\{\begin{array}{ccc}2x-3y=40&\text{multiply both sides by (-10)}\\23x-10y=12&\text{multiply both sides by 3}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-20x+30y=-400\\69x-30y=36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad49x=-364\qquad\text{divide both sides by 49}\\x=-\dfrac{364:7}{49:7}\\.\qquad\boxed{x=-\dfrac{52}{7}}$

$2\left(-\dfrac{52}{7}\right)-3y=40\\-\dfrac{104}{7}-3y=40\qquad\text{multiply both sides by 7}\\-104-21y=280\qquad\text{add 104 to both sides}\\-21y=384\qquad\text{divide both sides by (-21)}\\y=-\dfrac{384:3}{21:3}\\\boxed{y=-\dfrac{128}{7}}$

7 0

4 years ago