Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.
For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253
For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913
Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)
Answer:
min-mid-max-mid-min
-cosine
Step-by-step explanation:
This is the correct answer, further proof in the file attached.
Answer:
513.247
Step-by-step explanation:
I believe the answer is D
Answer:
The 2 numbers are 32 and 65.
Step-by-step explanation:
x + y = 97 where x and y are the 2 numbers.
x = 2y + 1
Substituting for x in the first equation:
2y + 1 + y = 97
3y = 96
y = 32.
So x = 2y + 1 = 64 + 1 = 65.
