Let x represent the digit in the hundreds place, y represent the digit in the tens place, and z represent the digit in the ones place. What do we know about each digit?
x: twice y (2, 4, 6, or 8)
y: half of x (1, 2, 3, or 4)
z: an even number (0, 2, 4, 6, or 8).
The sume of the digits is 14. So, x + y + z = 14
Choose one of the digits and look at your options (if any).
when x=2, then y = 1, which means z has to be 11 (NOT VALID)
when x=4, then y = 2, which means z has to be 8 (428 works!)
For fun, let's see if any other numbers work:
when x=6, then y = 3, which means z has to be 5 (NOT VALID)
when x=8, then y = 4, which means z has to be 2 (842 works!)
Answer: 428 and 842 both work
