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2 years ago

Is it c or d ?im confused on this question

Mathematics

1 answer:

sladkih [1.3K]2 years ago

8 0

It’s D, when lines are perpendicular, the slopes of the lines are opposite reciprocals.

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Please answer fast <br> needed as soon as possible

irakobra [83]

Answer:

Option B

Step-by-step explanation:

Equation of the graph,

f(x) = x²

If the graph is translated 5 units to the right,

g(x) = f(x - 5)

Therefore, g(x) = (x - 5)²

If the function 'g' is translated 3 units up,

h(x) = g(x) + 3

Therefore, h(x) = (x - 5)² + 3

If the function 'h' is vertically compressed by a factor of $\frac{2}{3}$ ,

Then the new function will be,

k(x) = $\frac{2}{3}(x-5)^2+3$

Option B will the correct option.

3 0

2 years ago

23X-4=20 Help please

k0ka [10]

Isolate both terms with "x" to the left side

23x -(4-4) = 20 + 4

23x - 0 = 24

its impossible to divide both ways because of 0 and 23 with 24 cant divide each other

so your answer would be

x = 23 over 24 or 23/24

hope this helps :D.

6 0

2 years ago

Write the expression as a single logarithm 7log(x) y + 6 log(b) x

daser333 [38]

Answer: $log(x)^{7y}+log(b)^{6x}=log(x^{7y}b^{6x}).$

Step-by-step explanation:

Given logarithm expression

$7log(x)^y + 6 log(b)^x.$

We need to write it as a single logarithm expression.

First we need to apply exponent rule of logs to remove 7 and 6 in front of logs.

$n log(p) = log(p)^n$

$7log(x)^y + 6 log(b)^x.= log(x)^{7y}+log(b)^{6x}$ .

Now, we need to apply product rule of logs $log(p)+log(q) = log(pq)$ .

$log(x)^{7y}+log(b)^{6x}=log(x^{7y}b^{6x}).$

Therefore, final answer is $log(x)^{7y}+log(b)^{6x}=log(x^{7y}b^{6x}).$

5 0

3 years ago

El peso que cargan tres pick-ups están en la razón de 2:6:7, cuánto carga el pick-up más grande, si el pick up menor carga 1500k

skad [1K]

Utilizando proporciones, hay que el pick-up más grande carga 5250 kg.

Este problema se resuelve por proporciones, por médio de una regla de três.

El peso que cargan tres pick-ups están en la razón de 2:6:7

2 + 6 + 7 = 15.
O sea, el pick-up menor carga $\frac{2}{15}$ de el total, que es equivalente a 1500 kg.
El pick-up más grande carga $\frac{7}{15}$ de el total, que es equivalente a x kg.