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3 years ago

How many distinct triangles can be formed for which m∠E = 64°, g = 9, and e = 10?

Mathematics

2 answers:

zysi [14]3 years ago

3 0

Answer:

1) one

2) zero

Step-by-step explanation:

e/sinE = g/sinG

10/sin64 = 9/sinG

sinG = 0.8089146417

G = 53.99

j/sinJ = k/sinK

3/sin129 = 8/sinK

sinK = 2.072389241

Zanzabum3 years ago

3 0

Answer:

First : 1

Second : 0

Step-by-step explanation:

Please give these stars to the person who did it before me. Thank you!

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Using the 10% value to find 20% of 300

neonofarm [45]

20% * 300 = 2 * (10% * 300) = 2*30 = 60

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3 years ago

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Anna35 [415]

Answer:

4 3/4 yards

Step-by-step explanation:

5 1/4 + 2 1/2 = 7 3/4

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2 years ago

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How many different 6-letter arrangements are possible using the letters in ALTUVE?

marshall27 [118]

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3 years ago

One Sunday, 120 days before Christmas, Aldsworth store publishes an advertisement saying ‘120 shopping days until Christmas'. Al

Lena [83]

Answer:

(a)18

(b)1089

(c)Sunday

Step-by-step explanation:

The problem presented is an arithmetic sequence where:

First Sunday, a=1
Common Difference (Every subsequent Sunday), d=7

We want to determine the number of Sundays in the 120 days before Christmas.

(a)In an arithmetic sequence:

$\text{The nth term}, T_n=a+(n-1)d\\T_n \leq 120\\$Therefore:$\\1+7(n-1) \leq 120\\1+7n-7\leq 120\\7n-6\leq 120\\7n\leq 120+6\\7n\leq 126\\$Divide both sides by 7$\\n\leq 18$

Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.

Therefore, Aldsworth advertised 18 times.

(b)Next, we want to determine the sum of the first 18 terms of the sequence

1,8,15,...

$\text{Sum of a sequence}, S_n=\frac{n}{2}( 2a+(n-1)d)\\S_{18}=\frac{18}{2}( 2*1+(18-1)*7)\\=9(2+17*7)\\=9(2+119)\\=9*121\\S_{18}=1089$

The sum of the numbers of days published in all the advertisements is 1089.

(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.

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3 years ago

Danny is measuring rainfalll.For a.Science project in september 7/8 inch of rain fell in october 2 1/4 invhes of rain fell how m

horsena [70]

Answer: $1\dfrac{3}{8}\ \text{inch}$

Step-by-step explanation:

Given

Rainfall in September is $\frac{7}{8}$ inch

Rainfall in October is $2\frac{1}{4}$ inch

Convert mixed fraction into fraction

$\Rightarrow 2\dfrac{1}{4}=\dfrac{9}{4}\ \text{inch}$

Difference between the two gives that how much more rain fall in October compared to September

$\Rightarrow \dfrac{9}{4}-\dfrac{7}{8}\\\\\Rightarrow \dfrac{18-7}{8}\\\\\Rightarrow \dfrac{11}{8}\ \text{inch or}\\\\\Rightarrow 1\dfrac{3}{8}\ \text{inch}$

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3 years ago