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lina2011 [118]
3 years ago
15

a farmer moved 43 cows from the field into a barn. now there are 48 cows in the field. how many cows were in the field before?

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
6 0
You must add the two numbers together and if you do so you would get the answer of 91 cows that were in the field before
ser-zykov [4K]3 years ago
3 0
The answer is 91 cows.
You add 43 and 48
43+48=91
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Step-by-step explanation:

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3 years ago
I need help with this!
Viefleur [7K]

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the answer is option E.

Step-by-step explanation:

it is in the form f/g (x).

we know f and g from the equation;

we can rewrite it as, (√(9-x^2)/(3x-1))

if you notice you cannot put any number less than -3 or greater than 3 in the numeror because if you do you get a negative root which is false. for instance if you put 4 or -4 in the numerator you get 9 - (4 or -4 square ) which is 9- 16 which is a negative number and you cannot take root of a negative number.

on the numerator if you put 1/3 as the value for x you will get zero in the denominator. and any number divided by zero is undefined so that cannot be.

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4 0
3 years ago
First person to answer the question correctly will get voted brainiest! PLEASE
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Step-by-step explanation:

$ 3750  = truck rental;   $125 per ton of sugar transported

 

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Equation relating C to S would be a linear equation like y = mx + b

 

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This equation would be graphed in the first quadrant only

 

you would start with your y-intercept at (0, 3750)

 

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(1, 3875)  (2, 4000)  (3, 4125)  etc.  

 

This shows that for each increase by one ton of sugar, the cost goes up $125

6 0
3 years ago
Read 2 more answers
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