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Pavlova-9 [17]
3 years ago
14

Find the volume of the cylinder

Mathematics
1 answer:
goblinko [34]3 years ago
5 0

Answer:  769.3ft³

Step-by-step explanation:

V = \pir²h

V = (3.14)(7)²(5)

V = 769.3ft³

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Is the equation x²+x+1 linear?
mr Goodwill [35]

Answer:

No.

A linear equation will not that any powers, in this case x².

This is a quadratic equation.

6 0
2 years ago
Which are the coordinates of point K?
never [62]
I need the graph first
3 0
3 years ago
Quadrilateral ABCD with vertices A(0, 6), B(-3, -6), C(-9, -6), and D(-12, -3): a) dilation with scale factor of 1/3 centered at
Oksanka [162]

a) The points of the new quadrillateral are A'(x,y) = (0, 2), B'(x,y) = (-1, -2), C'(x,y) = \left(-3,-2\right) and D'(x,y) = (-4, -1), respectively.

b) The points of the new quadrillateral are A'(x,y) = (-5, 5), B'(x,y) = (-8,-7), C'(x,y) = (-13, -7) and D'(x,y) = (-17, -4), respectively.

<h3>How to perform transformations with points</h3>

a) A dillation centered at the origin is defined by following operation:

P'(x,y) = k\cdot P(x,y) (1)

Where:

  • P(x,y) - Original point
  • P'(x,y) - Dilated point.

If we know that k = \frac{1}{3}, A(x,y) = (0,6), B(x,y) = (-3,-6), C(x,y) = (-9, -6) and D(x,y) = (-12, -3), then the new points of the quadrilateral are:

A'(x,y) = \frac{1}{3}\cdot (0,6)

A'(x,y) = (0, 2)

B'(x,y) = \frac{1}{3} \cdot (-3,-6)

B'(x,y) = (-1, -2)

C'(x,y) = \frac{1}{3}\cdot (-9,-6)

C'(x,y) = \left(-3,-2\right)

D'(x,y) = \frac{1}{3}\cdot (-12,-3)

D'(x,y) = (-4, -1)

The points of the new quadrillateral are A'(x,y) = (0, 2), B'(x,y) = (-1, -2), C'(x,y) = \left(-3,-2\right) and D'(x,y) = (-4, -1), respectively. \blacksquare

b) A translation along a vector is defined by following operation:

P'(x,y) = P(x,y) +T(x,y) (2)

Where T(x,y) is the transformation vector.

If we know that T(x,y) = (-5,-1), A(x,y) = (0,6), B(x,y) = (-3,-6), C(x,y) = (-9, -6) and D(x,y) = (-12, -3),

A'(x,y) = (0,6) + (-5, -1)

A'(x,y) = (-5, 5)

B'(x,y) = (-3, -6) + (-5, -1)

B'(x,y) = (-8,-7)

C'(x,y) = (-9, -6) + (-5, -1)

C'(x,y) = (-13, -7)

D'(x,y) = (-12,-3)+(-5,-1)

D'(x,y) = (-17, -4)

The points of the new quadrillateral are A'(x,y) = (-5, 5), B'(x,y) = (-8,-7), C'(x,y) = (-13, -7) and D'(x,y) = (-17, -4), respectively. \blacksquare

To learn more on transformation rules, we kindly invite to check this verified question: brainly.com/question/4801277

7 0
2 years ago
In an isosceles triangle the length of the base is 10 cm
lawyer [7]

The computation shows the radius of the circle that is inscribed in the isosceles triangle will be 3.33cm.

<h3>How to calculate the radius?</h3>

From the information given, the isosceles triangle the length of a base is 10 cm and the length of a leg is 13 cm.

Let A = area of the triangle

Let S = semi perimeter of the triangle.

The radius will be: = A/S

where,

S = \dfrac{(a + b + c)}{2} = \dfrac{(13 + 13 + 10)}{2} = 18

The radius will be:

 =\dfrac{(\sqrt{18} - \sqrt{13})(\sqrt{18} - \sqrt{13})(\sqrt{18} - \sqrt{10})} { 18}

= 3.33cm

In conclusion, the radius is 3.33cm.

Learn more about triangles on:

brainly.com/question/17335144

#SPJ4

5 0
2 years ago
A car dealer has 8 rows of cars with 16 cars in each. In each of the first 3 rows, 6 are used cars. The rest of the cars new car
qwelly [4]

The answer is 110 because if you multiply 8•16=128 and 18 cars are used, you subtract 128-18 which is 110.

8 0
3 years ago
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