The answer is A hope you get it right (:
Answer:
305 degree
Step-by-step explanation:
As AD and CE are the diameters of circle P, so that they intersect each other at point P.
=> So that ∡CPA and ∡DPE are two vertical angles.
=> ∡CPA = ∡DPE = 93 degree
As we can see, ∡CPA = ∡CPB + ∡BPA =38 + ∡BPA
=> ∡BPA = ∡CPA - 38 = 93 - 38 = 55 degree
As P is the centre of the circle, so that ∡BPA is equal to the measure of the arc AB, equal to 55 degree.
In the circle P, the total measure of arc AEB and arc AB are 360 degree
=> arc AEB + arc AB = 360
=> arc AEB = 360 - arc AB = 360 - 55 = 305
So that the measure of arc AEB is 305 degree
Answer:
Rational
Step-by-step explanation:
Answer:
ED = 4 units
Step-by-step explanation:
Observing the figure given to us, we can deduce the following:
=>CE = EA (because point E is the midpoint of CA)
Therefore, if CE = EA = x unit, CA = 2x
=>Also, CD = DB (because point D is the midpoint of CB)
Therefore, if CD = DB = y, CB = 2y
Thus, CA/CE = CB/CD = 2 (2x/x = 2y/y)
Going by the above ration we got comparing the ratio of the corresponding sides of ∆CAB and ∆CED (2:1), we can conclude that ∆CAB ~ ∆CED
Using the ratio of the corresponding sides of ∆CAB to ∆CED = (2:1), measure of segment ED is calculated below:
AB/ED = 2/1
8/ED = 2/1
Cross multiply
8 × 1 = 2 × ED
Divide both sides by 2
8/2 = ED
ED = 4 units
Find -4 on the number line.
Go to the right 6 place values (+6)
You will find your answer
-4 (+6) = 2
2 is your answer
hope this helps
