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bearhunter [10]
3 years ago
10

Solve the absolute value equation 3|2x+4| -1=11

Mathematics
1 answer:
hammer [34]3 years ago
4 0

3|2x+4| -1=11\\\\3|2x+4|=12\\\\|2x+4|=4\\\\|x+2|=2\\\\x+2=2 \vee x+2=-2\\\\x=0 \vee x=-4

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Marcus flipped a coin 800 times and it landed on heads 560 times. What us the relative frequency of the coin landing up based on
Sati [7]
When you said up do you mean heads? If you did the answer would be 70%.
8 0
4 years ago
Read 2 more answers
How do I find number 2?
prisoha [69]

Answer:

  y = 3/4x +4

Step-by-step explanation:

From point A to point B, you show a rise of 3 units and a run of 4 units. (The rise is the difference in height of the first two squares; the run is the side length of the first square.) The ratio rise/run = 3/4 is the slope of the line you want.

The upper-left corner of the first square is the y-intercept of the line (4). So, in slope-intercept form, the equation of the dotted line is ...

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8 0
4 years ago
How many terminal zeros does the integer equal to 80^16*75^8 have? PLZ HURRY DOING A TEST
avanturin [10]

Answer:

24 terminal zeros

Step-by-step explanation:

Here, we want to know the number of terminal zeros that the product if the integers above has

Terminal zeros refer to the zeros at the right of the last non zero digits

The product we are dealing with is;

80^16 * 75^8

80^16 itself has 16 terminal zeros

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3 0
3 years ago
Please help me I need it ​
Kitty [74]

Answer:(x - 1)(7x + 12)

Step-by-step explanation:

Question: (6x² + 5x - 3) + (x² - 9)

⇒(6x² + 5x - 3) + (x² - 9)

⇒6x² + 5x - 3 + x² - 9

rearrange

⇒6x² + x² + 5x - 3 - 9

⇒7x² + 5x - 12

Middle term break

⇒7x² + 12x - 7x - 12

⇒x(7x + 12) - 1(7x + 12)

⇒(x - 1)(7x + 12) Answer

hope that helps...

3 0
3 years ago
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Novay_Z [31]

Answer:

x=\pm \sqrt{11} \\y=-4.

Step-by-step explanation:

\left \{ {{3x^2+4y=17} \atop {2x^2+5y=2}} \right. \\\\Then\\\\\left \{ {{2 \times (3x^2+4y)=2 \times 17} \atop {3\times(2x^2+5y)=3\times2}} \right. \\\\\left \{ {{6x^2+8y=34 \quad (1)} \atop {6x^2+15y=6\quad (2)}} \right.\\\\(1)-(2) \Rightarrow -7y=28 \Rightarrow y =-4.\\Since \: \:  2x^2+5y=2 \Rightarrow 2x^2=2-5y\\\Rightarrow 2x^2=2+20=22\\\Rightarrow x^2=22:2=11\\\Rightarrow x=\pm \sqrt{11}.

7 0
3 years ago
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