Answer:
Step-by-step explanation:
One way to determine if the equation has any real solutions is to look at its discriminant. For the equation ax²+bx+c = 0, the discriminant is ...
d = b² -4ac
When the discriminant is negative, both solutions to the quadratic are complex. There are no real solutions in that case.
We can find the discriminant values to be ...
A: d = 2² -4(1)(4) = -12 . . . . no real zeros
B: d = 0² -4(3)(-5) = 60 . . . two real zeros
C: d = 8² -4(-2)(0) = 64 . . . two real zeros
D: d = 10² -4(1)(26) = -4 . . .no real zeros
Expressions A and D have no real zeros.
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<em>Comment on the question</em>
You are given an <em>expression</em>, not an <em>equation</em>. There is no equal sign. Hence, we cannot talk about <em>solutions</em>. We can only talk about <em>zeros</em>, values of x that make the expression have a value of zero.
Answer:
The distances between the three pairs of corresponding vertices for each movement must be equal. That is, if you translate points A to A', B to B', et cetera, the distance between A and A', and B and B' are the same.
A translation is a rigid transformation that moves vertices of a figure a fixed distance.
In a general way, a translation moves all points on a shape a fixed distance.
Answer:
#1a $391.50 #1b 14 years
Step-by-step explanation:
First, we add 25w on both sides to give us a positive expression for w:
Next, minus 200 from both sides to isolate the expression for w:
Now we divide by 25 on both sides to obtain the inequality for w:
So
