I think it’s B not rlly sure
Answer:
25cm³ = 0.025L of H2So4
Molarity of H2SO4 = 1moldm-³
Recall ... 1dm-³ = 1L
So the Molarity can also be 1mol/L
Mole = Molarity x volume in L
Mole of H2SO4 = 1mol/L x 0.025L
=0.025Moles of Sulphuric acid reacted.
From the equation of reaction
1mole of H2SO4 reacts to produce 1mole of Copper sulphate crystal
Since their Mole ratio is 1:1
It means that Since 0.025mole of H2SO4 reacted.... 0.025mole of CuSO4.5H2O would be produced
Nice.. OK
So we know the moles of CuSO4.5H2O produced
We can get the Mass
Recall
From
Mole=Mass/Molar Mass
Mass = Mole x Molar Mass
Molar Mass of CuSO4.5H2O = 64 + 32 + 16x4+ 5(2+16)
Mm= 250g/mol
Mass = 0.025mol x 250g/mol
= 6.25g of CuSO4.5H2O crystals Would be PRODUCED.
- A buffer solution resists the change in pH after the addition of small amounts of acid or base to it.
- The given buffer solution is NaHCO₃ (acid) + Na₂CO₃ (conjugate base).
- NaHCO₃ contains HCO₃⁻ and Na⁺ ions. Na₂CO₃ contains Na⁺ and CO₃²⁻ ions. Na⁺ ions do not show any effect on the pH of a solution.
Therefore, HCO₃⁻ and CO₃²⁻ are responsible for the buffer action.
HCO₃⁻ is the acidic component of the buffer. It neutralizes the small amounts of base added to it producing an equivalent amount of the conjugate base CO₃²⁻.
HCO₃⁻(aq) + OH⁻(aq) → CO₃²⁻(aq) + H₂O(l)
Acid conjugate base
CO₃²⁻ is the basic component if the buffer. It neutralizes the small amounts of acid added to it producing an equivalent amount of the conjugate acid HCO₃⁻
CO₃²⁻(aq) + H₃O⁺(aq) → HCO₃⁻(aq) + H₂O(l)
Base Conjugate acid
- Therefore, even after the addition of a small amount of acid or base to the buffer, pH remains unchanged.
Answer:
C meteoroid
Explanation:
Meteoroids are the only ones of the four that are under a kilometer in size.