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sukhopar [10]
3 years ago
12

Need help solving these questions

Chemistry
1 answer:
Anton [14]3 years ago
8 0

Answer:

1) 100

2) 22

3) 39

4) 6

5) 2b + 6

6) 8

7) 4n + 20

Explanation:

If B is the midpoint of AC and C is the midpoint of BD, means that all 3 parts are equal. AB = BC = CD

1) If AB = 50 then AC = AB + BC = 50 +50 = 100

2)if BD = 44 then is CD = 44 - BC ⇔ CD = 44 - 22 = 22

3) if AC = 26 and AC = AB + BC   then each part is 13  

AD = AC + CD = 26 +13 = 39

4)if CD = 6 then  AB = 6 Because all single parts are equal

5) if AC = 4b + 12 then is AB the half of it = 2b +6

6) if AD = 24 then AB = 1/3 of it = 8

7)if BC is 2n + 10 then is AC = 2x BC = 4n + 20

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Alisiya [41]
You have shown no structure, still we can work out for the answer :).

First Option: <span>2-dimethylyne: This name is incorrect, because it does not contain any parent chain name. 

Second Option: </span><span>2-methylbutane: I have drawn its structure below, compare it with your structure.

Third Option: </span>4-methylbutene:<span> I have drawn the structure for this name. But this name is also against IUPAC rules, and its correct name is 1-Pentene.

Fourth Option: </span><span>4,3-methylbutyne: Again incorrect name, 4,3 are two positions, but here only one substituent is given (methyl). I have drawn structure of 3,4-Dimethylbutene, this name is incorrect, and the correct name for this compound is 3-Methyl-1-pentene.

Fifth Option: </span><span>4,4-methylbutane: Again incorrect name, 4,4 means at 4 position two substituents, but in name only methyl is given. Anyhow lets make it two and draw a structure, for 4,4-Dimethylbutane. Ooops!! This name is also incorrect, and the correct name for this compound is 2-Methylpentane.

Result:
           Among all options only, option B (2-Methylbutane) is correctly named, and this will be the correct name for the structure given to you. </span>

8 0
3 years ago
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Classify the following aqueous solutions as: strong acid, weak acid, neutral, weak base, or strong base.
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Vinegar pH 3.2: Weak acid

Battery acid pH 0.5: Strong acid

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4 0
1 year ago
Accounting Concepts Should we buy stock in a company? Should we extend a line of credit to a company? Should we continue with cu
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1

Explanation:

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3 years ago
1. If the pressure of a fixed volume of gas decreased in a sealed container, what variable would you think changed? did this var
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Answer:

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Explanation:

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8 0
1 year ago
A sample of hydrogen gas at a pressure of 0.520 atm and a temperature of 26.2°C, occupies a volume of 15.4 liters. If the gas is
Oksanka [162]

Answer:

1.99 atm

Explanation:

Step 1:

Data obtained from the question. This include the following:

Initial pressure (P1) = 0.520 atm

Initial temperature (T1) = 26.2°C

Initial volume (V1) = 15.4L

Final temperature (T2) = constant = 26.2°C

Final volume (V2) = 4.02L

Final pressure (P2) =..?

Step 2:

Determination of the new pressure of the gas.

Since the temperature of the gas is constant, it means the gas is obeying Boyle's law. Thus, the new pressure of the gas can be obtained by applying the Boyle's law equation as shown below:

P1V1 = P2V2

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Divide both side by 4.02

P2 = (0.520 x 15.4) / 4.02

P2 = 1.99 atm

Therefore, the new pressure of the gas is 1.99 atm

4 0
3 years ago
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