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3 years ago

Wich is the measure of an angle that cuts off 1/4 of a circle

Mathematics

2 answers:

Pachacha [2.7K]3 years ago

4 0

There are 3 angles in that question. Which one are you talking about?

SOVA2 [1]3 years ago

3 0

Going around a full circle is 360.
1/4 of that is 90
So 90 degrees is 1/4 of a circle

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This one-dimensional figure goes on forever in two directions.

Vesna [10]

Please mark me Brainliest!

It should be B. line because line segment has a end and a Ray can only go in one direction forever while a line can go both directions forever.

Hope this helps!

5 0

3 years ago

Read 2 more answers

Use the distributive property to write an equivalent expression. 9(9x+2y-6)

Marizza181 [45]

Step-by-step explanation:

Multiply the number outside the brackets to the numbers inside:

So,

9 * 9x = 81x

9 * 2y = 18y

9 x -6 = -54

So the simplified or equivalent expression is:

81x + 18y - 54

4 0

2 years ago

Solve the following quadratic equation for its exact value by using the square root principle.

Korvikt [17]

Idk what the hell all that is but x = 1.802775637731995

4x^2 - 13 = 0

4x^2 = 13

13/4=3.25

x^2 = 3.25

x = ~1.8

5 0

3 years ago

two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe

sveta [45]

Applying the required rule or theorem, it can be concluded that the second biker is farther from the parking lot. The distance of the bikers to the parking lot are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The path of travel of both bikers would form a triangle. Applying the Pythagoras theorem to the path of the first biker would give his distance from the starting point. While applying the cosine rule to the path of second rider would gives his distance to the starting point.

Thus,

a. To determine the distance of the first biker from the parking lot.

Let the required distance be represented by x. Applying the Pythagoras theorem, we have:

$hyp^{2}$ = $adj 1^{2}$ + $adj 2^{2}$

$x^{2}$ = $8^{2}$ + $15^{2}$

= 64 + 225

= 289

x = $\sqrt{289}$

= 17

x = 17 km

Thus, the first biker is 17.0 km from the starting point.

b. To determine the distance of the second biker from the parking lot.

Let the required distance be represented by x. So that applying the cosine rule, we have:

$c^{2}$ = $a^{2}$ + $b^{2}$ - 2ab Cos θ

$x^{2}$ = $8^{2}$ + $15^{2}$ - 2(15*8) Cos (180 - 20)

= 64 + 225 - 240 Cos 160

= 289 - 240 * -0.5

$x^{2}$ = 289 + 120

= 409

x = $\sqrt{409}$

= 20.2237

x = 20.22 km

Thus, the second biker is 20.22 km from the starting point.

Therefore, the second biker is farther from the parking lot.

A sketch of the path of travel for the two bikers is attached for more clarifications.

Visit: brainly.com/question/22699651

7 0

2 years ago

Distributive property 3(x-1)=3x-

user100 [1]

The answer is 3x-3. You have to distribute the 3 to both of the variables in the equations. The 1 in the parentheses is a negative and multiplying the 3 will result in a negative 3.

5 0

3 years ago