Question

P URGENT I've got a timer going on but really need your help to answer this thank you!!

Answer 1

Given:

The radius of inner circle = 13 yd.

The width of the shaded region = 8 yd

To find the area of the shaded region.

Now,

The radius of the outer circle = 13+8 yd = 21 yd

Formula

The area of a circle of radius r unit is $\pi r^{2}$ sq unit.

$A = A_{1}-A_{2}$

where, $A$ = The area of the shaded region

$A_{1}$ = Area of the outer region

$A_{2}$= Area of the inner region

Now,

$A_{1}$$=$ $\pi (21^{2})$

$A_{1} = (3.14)(21)(21)$

$A_{1}$$= 1384.74$ sq yd

And,

$A_{2}$ $=$ $\pi (13^{2})$

$A_{2} = (3.14)(13)(13)$

$A_{2}$$= 530.66$ sq yd

Therefore,

$A = 1384.74-530.66$ sq yd

$A = 854.08$ sq yd

Hence,

The area of the shaded region 854.08 sq yd.