The function F(x) =3/(x-3)(x+3) is never equal to zero.
1 answer:
Answer:
F(x) =3/(x-3)(x+3) ≠ 0
Step-by-step explanation:
This is true because f(x) can't be 0 due to the numerator being 3. If it were possible, the denominator would be 0 so 3/0 = undefined, which is impossible.
I graphed the equation on the graph below.
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Answer: The amount of tea ounces that sells for $ 3.25 is 36, and the amount of tea ounces that sells for $ 2.50 is 54.
Step-by-step explanation:
We start by defining variables from the data provided:
a = amount of ounces of tea that sells for $ 3.25
b = amount of ounces of tea that sells for $ 2.50
c = amount of ounces of tea that sells for $ 2.80
From the problem we know that , and that
. You can propose a system of equations:
Having the fact that c = 90, we can simplify the system:
Clearing a in the first equation we get:
And substituting in the second equation we arrive at:
Now we can use b in the first equation to get a:
We verify that , and that
.