Answer:
I assume you know Arithmetic Progression .
so, we have to find the first and last 4-digit number divisible by 5
first = 1000 , last = 9990
we have a formula,
= a + (n-1)d
here,
is the last 4-digit number divisible by 5.
n is the number of 4-digit even numbers divisible by 5
d is the common difference between the numbers, which is 10 in this case
a is the first 4-digit number divisible by 5
9990 = 1000 + (n-1)*10
899 = n-1
n = 900
Hence, there are 900 4-digit even numbers divisible by 5
Answer:
No
Step-by-step explanation:
Direct variation: two variables, one variable is a constant multiple of another variable
y = k x .... k constant
-x+4y=-2
4y = x - 2
y = 1/4 x -1/2 ..... y = k x + b y is not a simple multiple of x
Look at the graph thoroughly .
It passes through origin and given some points
(-1,1)
(1,-1)
(2,-2)
(-2,2)
We observe that

Hence whatever the function be the result will be -x
Option D is correct
Answer:
pqr²+pr-rp²+rq²
Step-by-step explanation:
pq(r²+1)-r(p²+q²)
pqr²+pr-rp²+rq²