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ioda
4 years ago
12

Help me plz cant figure this out

Mathematics
2 answers:
dezoksy [38]4 years ago
6 0
Im not that good at these, but i thibk that its the 1st, 3rd, and 4th options.

i may be wrong so forgive me if i am :)
babymother [125]4 years ago
3 0
Rays CA and CB form the angle ACB
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BRAINLIESTTT ASAP! :)
serious [3.7K]
Ok so basically I dunno all the corr. coefict stuff, but...
in 10 sec it went for 4 to 8, that's doubled
then from 8 to 12 is, +4, 4×3

A. Just during these two intervals we have, y/x: 4/10, then 8/20, then 12/30
0.4, 0.4, 0.4, but then it goes 15/30 = 0.5
so it's not a perfect 100% (1.00) correlation, but it would be very close [I'd choose b) 0.99]

B. from 10-30mins, it went from 4 to 8 to 12
m = change in y ÷ change in x
m = (12-4)/(30-10) = 8/20 = 0.40

C. means that the rate there is 0.40 miles per min. steady, which is 0.40 miles/min × 60min/hr = 24mi/hr steadily without increase or decrease, but a slight decrease from 30-40
RARELY say Causation, Ehr on the side of caution... correlation when in doubt
6 0
3 years ago
Pls help me i’ll give brainliest
liq [111]

Answer:

The First One! ✨

Step-by-step explanation:

Brainliest pls- ig-

5 0
3 years ago
A football field is marked every 5 yards. Garret ran from the 1st mark to the 11th mark. Which shows the correct way to find the
svlad2 [7]

Answer:

150 feet

Step-by-step explanation:

There are 10 marks between the 1st and 11th mark.

Since each mark represents 5 yards, 10 * 5 = 50 yards

Since 1 yard = 3 feet

50 yards = 50 * 3 = 150 feet

8 0
4 years ago
A)Agudos<br> B)suplementares <br> C)congruentes<br> D)complementares <br> E)Rasos
True [87]

Answer:

The correct answer to this question is complementars

8 0
3 years ago
1) Factor the expression and use the fundamental identities to simplify. There is more than one correct form of the answer.
Art [367]

Answer:

Step-by-step explanation:

1) 6 tan2x − 6 tan2x sin2x

=6tan2x(1-sin2x)\\= 6tan2x (sin^2 x + cos^2 x -2sinx cosx)\\= 6tan2x (sinx+cosx)^2\\

2) \frac{3}{1+cos x} +\frac{3}{1-cosx} \\=\frac{3-cosx+3+cosx}{1-cos^2 x} \\=\frac{6}{sin^2 x} \\=6 cosec^2 x

3) \frac{sin^2 y}{1-cosy } =\frac{1-cos^2 y}{1-cosy }\\=1+cosy

4) x=6cos t

So cost =x/6

sint = \frac{\sqrt{36-x^2} }{\{6 } \\

so -3sint

5)

4 0
3 years ago
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