Answer:
The inverse function of 3x - 4 is (x+4)/3. so a
Step-by-step explanation:
f(x) = 3x - 4
y = 3x - 4 replace f(x) with y
x = 3y - 4 replace x with y and y with x.
3y = x + 4 solve for y
y = (x+4)/3 replace y with f-1(x)
f-1(x) = (x+4)/3
Complete question :
Suppose there are n independent trials of an experiment with k > 3 mutually exclusive outcomes, where Pi represents the probability of observing the ith outcome. What would be the formula of an expected count in this situation?
Answer: Ei = nPi
Step-by-step explanation:
Since Pi represents the probability of observing the ith outcome
The number of independent trials n = k>3 :
Expected outcome of each count will be the product of probability of the ith outcome and the number of the corresponding trial.
Hence, Expected count (Ei) = probability of ith count * n
Ei = nPi
Answer:
i think the answer is 23
Step-by-step explanation:
well the equation says c=45+7n so the total cost is 206 . i subtracted 45 from 206 leaving me with 161 then i divided that by 7 leaving me with 23
I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.
A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.
Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.
The number of ways of drawing 2 aces and 3 2s is

and the number of ways of drawing 3 aces and 2 2s is the same,

so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.
Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is

The total number of hands that can be drawn is

Then the probability of getting a full house is

Answer:
-3.274
Step-by-step explanation:
attached
Hopes this helps
{please mark me brainiest}