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3 years ago

What is the circumference of the circle in terms of pi? The radius is 2.2

2 answers:

6 0

We will use formula for circumference of circle:
lets name it as O

O = 2*r * pi

when we express r in this formula we get:

O = 2*2.2*pi
O = 4.4*pi

From this we can see that for given radius, answer is 4.4. The formula only depends on pi and that is what "in terms of pi" means.

oksian1 [2.3K]3 years ago

6 0

I hope this helps you

circumference=pi.r^2

circumference=pi. (2,2)^2

circumference=4,84.pi

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Help please show the work if you can

Vlada [557]

Answer:

The inverse function of 3x - 4 is (x+4)/3. so a

Step-by-step explanation:

f(x) = 3x - 4

y = 3x - 4 replace f(x) with y

x = 3y - 4 replace x with y and y with x.

3y = x + 4 solve for y

y = (x+4)/3 replace y with f-1(x)

f-1(x) = (x+4)/3

8 0

2 years ago

Suppose there are n independent trials of an experiment with k3 mutually exclusive outcomes, where pi represents the probabilit

sasho [114]

Complete question :

Suppose there are n independent trials of an experiment with k > 3 mutually exclusive outcomes, where Pi represents the probability of observing the ith outcome. What would be the formula of an expected count in this situation?

Answer: Ei = nPi

Step-by-step explanation:

Since Pi represents the probability of observing the ith outcome

The number of independent trials n = k>3 :

Expected outcome of each count will be the product of probability of the ith outcome and the number of the corresponding trial.

Hence, Expected count (Ei) = probability of ith count * n

Ei = nPi

8 0

3 years ago

The total cost C dollars, that a shop charges to print T shirts C = 45 + 7n , is the number of shirts ordered. Coach Dell paid 2

Lesechka [4]

Answer:

i think the answer is 23

Step-by-step explanation:

well the equation says c=45+7n so the total cost is 206 . i subtracted 45 from 206 leaving me with 161 then i divided that by 7 leaving me with 23

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2 years ago

Find the probability of being dealt a full house. (Round your answer to six decimal places.)?

vesna_86 [32]

I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.

A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.

Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.

The number of ways of drawing 2 aces and 3 2s is

$\dbinom42\dbinom43=24$

and the number of ways of drawing 3 aces and 2 2s is the same,

$\dbinom43\dbinom42=24$

so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.

Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is

$2\dbinom{13}2\dbinom42\dbinom43=3744$