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daser333 [38]
2 years ago
14

Find the area (shaded) and round to the tenths place if necessary.

Mathematics
1 answer:
Irina18 [472]2 years ago
3 0

Answer:

28.3

Step-by-step explanation:

A = π r²

r(radius)=3

r²=3²=9

9*π=28.2743338823

now round 28.2743338823=28.3

The area of this circle is 28.3

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The anwer plus working is 6668/4=151.55
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3 years ago
Find the area of the irregular shape. Round to the nearest tenth.
svp [43]
Given: 
Irregular Shape: 
Semi-circle and rectangle:

Area of a rectangle = l * w
Area of a semi-circle = (π r²)/2

Area of rectangle = 8 cm * 5 cm = 40cm²
Area of a semi-circle = (3.14 (4²))/2 = (3.14*16)/2 = 50.24/2 = 25.12cm²
4² is taken from diameter of 8cm divided by 2 to get the radius.

Total area = 40 cm² + 25.12 cm² = 65.12 cm²
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3 years ago
Please help me I can’t figure them out
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Where is the question
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3 years ago
Maristella is constructing an isosceles triangle to use as a model in her Algebra class. The perimeter of her triangle is 24 cm.
Vlada [557]

Isolating s, the equation written in terms of s is:

s = 12 - 0.5b

-------------------------

  • The equation for the length of the third side, as stated in the problem,("Maristella uses the equation b = 24 – 2s to find b, the length of the triangle's third side") is:

b = 24 - 2s

  • To solve for the lengths of the congruent sides, we isolate s, thus:

b = 24 - 2s

2s = 24 - b

Inverse of multiplication is division, thus:

s = \frac{24 - b}{2}

Separating into two fractions:

s = \frac{24}{2} - \frac{b}{2}

Solving each fraction:

s = 12 - 0.5b

A similar problem is given at brainly.com/question/5123313

3 0
3 years ago
What is the slope- intercept form equation of the line that passes through (5, 7) and (8, 22)
kap26 [50]
M = (22 - 7)/(8 - 5) = 15/3 = 5 
<span>using point (5, 7) </span>
<span>y - 7 = 5(x - 5) in point-slope form </span>
<span>y - 7 = 5x - 25 </span>
<span>y = 5x - 18 in slope-intercept form.</span>
3 0
3 years ago
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