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snow_lady [41]
3 years ago
13

The selling price, s, of an item is s = c + mc, where c is the cost of the item and m is the percent markup based on cost. What

is the formula solved for m?
Mathematics
2 answers:
levacccp [35]3 years ago
7 0
S=c+mc
s-c=mc
(s-c)/c=m
m=(s-c)/c
Sladkaya [172]3 years ago
4 0

Answer:

m=\frac{s-c}{c}

Step-by-step explanation:

The given expression is

s=c+mc

Now, to find the expression for m, we just have to isolate it. First, we have to move the term c to the other side of the equation, and then to move the coefficient c, which is gonna pass to the other side dividing.

s=c+mc\\s-c=mc\\\frac{s-c}{c}=m\\m=\frac{s-c}{c}

Therefore, the percent markup is defined as the difference between the selling price and cost, divided by that cost.

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The area of rectangle ABCD is represented by the expression 2x2 – 13x + 21. The area of rectangle WXYZ is represented by the exp
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Nemecek Brothers make a single product on two separate production lines, A and B. Its labor force is equivalent to 1000 hours pe
frez [133]

Answer:

(a) The inequality for the number of items, x, produced by the labor, is given as follows;

250 ≤ x ≤ 600

(b) The inequality for the cost, C is $1,000 ≤ C ≤ $3,000

Step-by-step explanation:

The total time available for production = 1000 hours per week

The time it takes to produce an item on line A = 1 hour

The time it takes to produce an item on line B = 4 hour

Therefore, with both lines working simultaneously, the time it takes to produce 5 items = 4 hours

The number of items produced per the weekly labor = 1000/4 × 5 = 1,250 items

The minimum number of items that can be produced is when only line B is working which produces 1 item per 4 hours, with the weekly number of items = 1000/4 × 1 = 250 items

Therefore, the number of items, x, produced per week with the available labor is given as follows;

250 ≤ x ≤ 1250

Which is revised to 250 ≤ x ≤ 600 as shown in the following answer

(b) The cost of producing a single item on line A = $5

The cost of producing a single item on line B = $4

The total available amount for operating cost = $3,000

Therefore, given that we can have either one item each from lines A and B with a total possible item

When the minimum number of possible items is produced by line B, we have;

Cost = 250 × 4 = $1,000

When the maximum number of items possible, 1,250, is produced, whereby we have 250 items produced from line B and 1,000 items produced from line A, the total cost becomes;

Total cost = 250 × 4 + 1000 × 5 = 6,000

Whereby available weekly outlay = $3000, the maximum that can be produced from line A alone is therefore;

$3,000/$5 = 600 items = The maximum number of items that can be produced

The inequality for the cost, C, becomes;

$1,000 ≤ C ≤ $3,000

The time to produce the maximum 600 items on line A alone is given as follows;

1 hour/item × 600 items = 600 hours

The inequality for the number of items, x, produced by the labor, is therefore, given as follows;

250 ≤ x ≤ 600

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3 years ago
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Answer:

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-2/5 -x -9/10

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