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morpeh [17]
3 years ago
13

Cody can paint a 15 ft. by 18 ft. wall in 50 minutes. He had to paint eight of these walls in his house. If he finished at 7:40

p.m., what time did Cody begin?
A. Noon
B. 1:00 pm
C. 2:00 pm
D. 3:00 pm
Mathematics
2 answers:
aivan3 [116]3 years ago
4 0
The answer is going to be 1:00 because u multiply 50*8=400 minutes 
400 Minutes=6 hours and 40 minutes then you subtract 
7-6=1 and add the forty minutes 
Hopes this helps:)
Bingel [31]3 years ago
3 0
I hope this helps you




8×50=400 minutes





1 hour 60 minutes




? hours 400 minutes



?.60=400


?=6,66



7.40-7 hour 6 minutes



00.34pm
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What is the volume of a sphere with a diameter of 10 m, rounded to the nearest tenth of a cubic meter
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Answer:

4188.8 cm^3

Step-by-step explanation:

We can calculate the volume of a sphere by using the following equation:

\frac{4}{3}\pi  r^{3}

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so let's just plug in what we know

4/3(pi)(10)^3

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A rectangle has perimeter 28cm. Its area is 42sq.cm. Determine the dimensions of the rectangle. Include a diagram in your soluti
yawa3891 [41]

The dimensions of the rectangle are: b=9.65 cm and h=4.35 cm or b=4.35 cm and h= 9.65 cm.

<h3>Quadrilaterals</h3>

There are different types of quadrilaterals, for example, square, rectangle, rhombus, trapezoid, and parallelogram.  Each type is defined accordingly to its length of sides and angles. For example, in a rectangle,  the opposite sides are equal and parallel and their interior angles are equal to 90°.

The area of a rectangle is equal to base x height (A=bh). The perimeter of a geometric figure is the sum of its sides. Thus, for a rectangle, the perimeter is 2b+2h.

<h3>System of Linear Equations</h3>

System of linear equations is the given term math for two or more equations with the same variables. The solution of these equations represents the point at which the lines intersect.

The question gives:

Perimeter=28cm

Area= 42 cm²

If the perimeter is the sum of all sides of the rectangle, you have:

Perimeter= 2b+2h=28

If the area of the rectangle is 42cm², you have:

Area=bh=42 cm²

You can write a system of linear equations.

2b+2h=28 (1)

bh=42 (2)

From equation 2, you have  b=\frac{42}{h}. Then, you can replace it in equation 1.

2*\frac{42}{h}+2h=28 \\ \\ 84+2h^2=28h\\ \\ 2h^2-28h+84=0 \; dividing\; by\; 2\\ \\ h^2-14h+42=0

Now, you should solve the quadratic equation.

h_{1,\:2}=\frac{-\left(-14\right)\pm \sqrt{\left(-14\right)^2-4\cdot \:1\cdot \:42}}{2\cdot \:1}

h_{1,\:2}=\frac{-\left(-14\right)\pm \:2\sqrt{7}}{2\cdot \:1}

h_1=\frac{-\left(-14\right)+2\sqrt{7}}{2\cdot \:1}=7+\sqrt{7}=9.65 cm

h_2=\frac{-\left(-14\right)-2\sqrt{7}}{2\cdot \:1}=7-\sqrt{7}=4.35cm

If h1=9.65 cm, then b_1=\frac{42}{9.65} =4.35 cm, and if  h2=4.35 cm, then b_1=\frac{42}{4.35} =9.65 cm.

Read more about the quadratic function here:

brainly.com/question/1497716

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2 years ago
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Nana76 [90]
457 irk sorry I don’t do this
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3 years ago
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4

Step-by-step explanation:

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