
Let

The curl is

where
denotes the partial derivative operator with respect to
. Recall that



and that for any two vectors
and
,
, and
.
The cross product reduces to

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

which means
is indeed conservative and we can find
.
Integrate both sides of

with respect to
and

Differentiate both sides with respect to
and




Now

and differentiating with respect to
gives




for some constant
. So

When turning a fraction into a decimal, any whole numbers comes before the "." and the fraction will become after the ".".
To make it simple, turn the fraction into a "over 100" fraction to make it easier.
Multiple both numeriator and denominator by a specific number, to turn the denominator into a 100. You must times the numeriator as well since your changing the denominator.
100 / 5 = 20
So now, multiple both sides of the fraction by 20.
3 x 20 = 60
5 x 20 = 100
2 60/100
Now, put the whole number in front of the decimal symbol.
2.___
Now, take the numeriator and put it behind the decimal symbol.
2.60
So, when turning 2 3/5 into a decimal, it is 2.60.
Answer:
q¹²
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Exponential Rule [Powering]:

Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
(q⁶)²
<u>Step 2: Simplify</u>
- Exponential Rule [Powering]: q⁶⁽²⁾
- [Exponents] Multiply: q¹²
Answer:
Option C
Step-by-step explanation:
Given the following question:
Total cost is $725
15% Marcus makes in commission.
In order to find the answer, we have to find 15% of $725 and that number will be the total in commissions he earned that week.

Marcus makes "$108.75" or option C in commissions last week.
Hope this helps.
Answer:
1.22
Step-by-step explanation:
- Subtract 1.3 from each side, so it now looks like this: 5g = 6.1
- Divide each side by 5, so it now looks like this: g = 1.22
I hope this helps!