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Oksi-84 [34.3K]

3 years ago

10

How do I factor this equation?

1 answer:

larisa86 [58]3 years ago

7 0

Answer:

Try your best bud.. You can do it!

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if BA is extended all the way through A creating BF and A becomes the midpoint of BF, then what are the coordinates of F

gogolik [260]

Answer:

$F(2x_A-x_B,2y_A-y_B)$

Step-by-step explanation:

Let points A, B and F have coordinates $A(x_A,y_A),$ $B(x_B,y_B)$ and $F(x_F,y_F).$

If BA is extended all the way through A creating BF and A becomes the midpoint of BF, then the midpoint A of the segment BF has coordinates:

$\dfrac{x_B+x_F}{2}=x_A\\ \\\dfrac{y_B+y_F}{2}=y_A$

Express coordinates of point F:

$x_B+x_F=2x_A\Rightarrow x_F=2x_A-x_B\\ \\y_B+y_F=2y_A\Rightarrow y_F=2y_A-y_B$

Hence,

$F(2x_A-x_B,2y_A-y_B)$

3 0

3 years ago

Suppose that the function f(x)=4x-2 represents the cost to rent x movies a month from an internet movie club. Laticia now has $1

Simora [160]

Not really sure i am sorry

5 0

3 years ago

Vi) Briefly explain the effects of migration in various areas.<br>

Tresset [83]

Answer:

first it is not a maths question

second the ans to the question

Step-by-step explanation:

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4 0

3 years ago

Given the recursive formula for an arithmetic sequence find the common difference and the 52nd term

Mice21 [21]

Answer:

Common difference(d) $a_{52}$

(21) -10 -548

(22) -7 -323

(23) 10 547

(24) -100 -5118

Step-by-step explanation:

Let the common difference be denoted by 'd'.

Also the nth difference of an arithmetic sequence is given by: $a_{n}=a_{1}+(n-1)\times d$

(21)

We are given a recursive formula as:

$a_{n}=a_{n-1}-10$

The first term is given by:

$a_{1}=-38$

The common difference for an arithmetic sequence is given by:

$a_{n}-a_{n-1}$

Hence, here we have the common difference as:

$d=-10$

The nth term of an arithmetic sequence is given by:

$a_{n}=a_{1}+(n-1)\times d$

Here $a_{1}=-38$ and $d=-10$ .

Hence, $a_{52}=-38+(52-1)\times (-10)$

Hence, $a_{52}=-548$

(22)

$a_{n}=a_{n-1}-7$

$a_{1}=34$

The common difference for an arithmetic sequence is given by:

$a_{n}-a_{n-1}$

Hence, here we have the common difference as:

$d=-7$

Here $a_{1}=34$ and $d=-7$ .

Hence, $a_{52}=34+(52-1)\times (-7)$

Hence, $a_{52}=-323$

(23)

$a_{n}=a_{n-1}+10$

$a_{1}=37$

The common difference for an arithmetic sequence is given by:

$a_{n}-a_{n-1}$

Hence, here we have the common difference as:

$d=10$

Here $a_{1}=37$ and $d=10$ .

Hence, $a_{52}=37+(52-1)\times (10)$

Hence, $a_{52}=547$

(24)

$a_{n}=a_{n-1}-100$

$a_{1}=-18$

The common difference for an arithmetic sequence is given by:

$a_{n}-a_{n-1}$

Hence, here we have the common difference as:

$d=-100$

Here $a_{1}=-18$ and $d=-100$ .

Hence, $a_{52}=-18+(52-1)\times (-100)$

Hence, $a_{52}=-5118$

5 0

4 years ago

PLEASE HELP!! Need help with my homework!

gulaghasi [49]

Answer:

Line segment: AD (without arrow)

Ray: BA (with one sided arrow)

Rays with common endpoint: AC and AD (with one sided arrow)

Intersection: AE (double sided arrow)

Collinear points: B, A, C

PLEASE MARK AS BRAINLIEST

6 0

3 years ago