Answer:
2 / (x + 1).
Step-by-step explanation:
If the number is represented by x the expression is:
2 / (x + 1).
Answer:
k ≥2
Step-by-step explanation:
k+ 1/3≥7/3
Subtract 1/3 from each side
k+ 1/3-1/3≥7/3-1/3
k ≥6/3
k ≥2
1-2. The best estimate for the population mean would be sample mean of 60 gallons. Since we know that the sample mean is the best point of estimate. Since sample size n=16 is less than 25, we use the t distribution. Assume population from normal distribution.
3. Given a=0.1, the t (0.05, df = n – 1 = 15)=1.75
4. xbar ± t*s/vn = 60 ± 1.75*20/4 = ( 51.25, 68.75)
5. Since the interval include 63, it is reasonable.
Answer:
The third one.
Explanation:
A dilation is a shrink or a stretch of a figure.
In a dilation, all sides either increase or decrease by the same scale factor. Additionally, in a dilation the angle measures of the figure do not change.
In the first figure, we can see that the base angles of the pre-image are slightly different than those of the image. This is not a dilation.
In the second figure, the angles are noticeably different; again, not a dilation.
In the fourth figure, much like the second figure, the angles are noticeably different. This is not a dilation.
In the third figure, however, we can see that the slanted sides of the larger figure go through three boxes; they are three units long. Additionally we can see that the slanted sides of the smaller figure go through 1 side; this is a dilation b a factor of 3.
The base sides of the third figure, in the larger shape, are 6 units long; in the smaller figure, they are 2 units long. This is a dilation by a factor of 3.
Answer:
The answer is below
Step-by-step explanation:
12 inches = 1 ft.
6 inches = 6 inches * (1 ft./12 inches) = 0.5 ft.
Therefore the diameter of the cast iron (D) = 6 inches = 0.5 ft.
The area of cast iron (A) = πD²/4 = π(0.5)²/4 = 0.196 ft²
The velocity (V) = 6 ft./s, the acceleration due to gravity (g) = 32.2 ft./s²
ε/D = 0.0004 ft./ 0.5 ft. = 0.0008
Using the moody chart, find the line ε/D = 0.0008 and determine the point of intersection with the vertical line R = 2.7 * 10⁵. Hence we get f = 0.02.
The head loss (h) is:
![h_f=f*\frac{L}{d}* \frac{V^2}{2g}=0.02*\frac{200\ ft}{0.5\ ft} *\frac{(6\ ft/s)^2}{2*32.2\ ft/s^2}=4.5\ ft](https://tex.z-dn.net/?f=h_f%3Df%2A%5Cfrac%7BL%7D%7Bd%7D%2A%20%5Cfrac%7BV%5E2%7D%7B2g%7D%3D0.02%2A%5Cfrac%7B200%5C%20ft%7D%7B0.5%5C%20ft%7D%20%2A%5Cfrac%7B%286%5C%20ft%2Fs%29%5E2%7D%7B2%2A32.2%5C%20ft%2Fs%5E2%7D%3D4.5%5C%20ft)
The pressure drop (Δp) is:
Δp = ρg
= ![(62.4\ lbf/ft^3)(4.5\ ft)= 280\ lbf/ft^2](https://tex.z-dn.net/?f=%2862.4%5C%20lbf%2Fft%5E3%29%284.5%5C%20ft%29%3D%20280%5C%20lbf%2Fft%5E2)