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aleksklad [387]

3 years ago

13

A chef cooks 4 pounds of pasta. She serves 1/8 pound of pasta on each plate: What is the total number of plates the chef serves

with 4 pounds of pasta??

2 answers:

kolezko [41]3 years ago

8 0

32 plates of pasta is served

masha68 [24]3 years ago

5 0

Answer:

8 × 1/8 = 1

4 × 8 = 32

32 plates

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A parcel delivery service will deliver a package only if the length plus girth (distance around) does not exceed 84 in. What are

Lesechka [4]

Answer:

a) $\frac{28}{\pi}$ in

b) 28 in

c) 784 in²

Step-by-step explanation:

Let the length be 'L'

and the radius be 'r'

Thus, according to the question

L + 2πr = 84 in

L = 84 - 2πr ............(1)

Volume of the cylinder, V = πr²L

substituting the value of L from 1, we get

V = πr²(84 - 2πr)

or

V = 84πr² - 2π²r³

for points of maxima, differentiating the above equation and equating it to zero

$\frac{dV}{dr}=\frac{d(84\pi r^2-2\pi^2 r^3))}{dr}$

or

2(84)πr - 3(2)π²r² = 0

or

2πr(84 - 3πr) = 0

or

r = 0 and 84 - 3πr = 0

or

⇒ 3πr = 84

or

⇒ r = $\frac{28}{\pi}$ in

since, the radius cannot be zero therefore, r = 0 is neglected

Therefore,

a) The radius of the largest cylindrical package = $\frac{28}{\pi}$ in

b) from (2)

L = 84 - 2πr

or

⇒ L = $84 - 2\pi\times\frac{28}{\pi}$

or

⇒ L = 84 - 56 = 28 in

The length of the largest cylindrical package = 28 in

c ) The volume of the largest cylindrical package ,V = πr²L

= $\pi\times\frac{28}{\pi}\times28$

= 784 in²

7 0

3 years ago

Sociologists say that 85% of married women claim that their husband's mother is the biggest bone of contention in their marriage

hoa [83]

Answer:

(A) 0.377,

(B) 0.000,

(C) 0.953,

(D) 0.047

Step-by-step explanation:

We assume that having a bone of intention means not liking one's Mother-in-Law

(A) P(all six dislike their Mother-in-Law) = (85%)^6 = (.85)^6 = 0.377

(B) P(none of the six dislike their Mother-in-Law) =

(100% - 85%)^6 =

0.15^6 =

0.000

(C) P(at least 4 dislike their Mother-in-Law) =

P(exactly 4 dislike their Mother-in-Law) + P(exactly 5 dislike their Mother-in-Law) + P(exactly 6 dislike their Mother-in-Law) =

C(6,4) * (.85)^4 * (1-.85)^2 + C(6,5) * (.85)^5 * (.15)^1 + C(6,6) * (.85)^6 = (15) * (.85)^4 * (.15)^2 + (6) * (.85)^5 * .15 + (1) * (.85)^6 =

0.953

(D) P(no more than 3 dislike their Mother-in-Law) =

P(exactly 0 dislikes their Mother-in-Law) + P(exactly 1 dislikes her Mother) + P(exactly 2 dislike their Mother-in-Law) + P(exactly 3 dislike their Mother-in-Law) =

C(6,0) * (.85)^0 * (.15)^6 + C(6,1) * (.85)^1 * (.15)^5 + C(6,2) * (.85)^2 * (.15)^4 + C(6,3) * (.85)^3 * (.15)^3 =

(1)(1)(.15)^6 + (6)(.85)(.15)^5 + (15)(.85)^2 *(.15)^4 + (20)(.85)^3 * (.15)^3 =

0.047

3 0

3 years ago

A new sales training program has been instituted at a rent-to-own company. Prior to the training, 10 employees were tested on th

Lunna [17]

Answer:

C. H0: µD = 0, HA: µD <0

Step-by-step explanation:

We assume that the paired sample data are simple random samples and that the differences have a distribution that is approximately normal. So for this case is better apply a paired t test.

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.

Let put some notation

x=test value for pretest , y = test value for posttest

x: 66, 94, 87, 84, 76, 88

y: 75, 100, 93, 85, 75, 90

The system of hypothesis for this case are:

Null hypothesis: $\mu_D \geq 0$

Alternative hypothesis: $\mu_D < 0$

Because the difference D is defined as Pretest-Postest. And we want to see if the postets score is higher than the pretest with th training.

The first step is calculate the difference $d_i=x_i-y_i$ and we obtain this:

d: -9, -6, -6, -1, 1, -2

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{-23}{6}=-3.833$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =3.763$

The 4 step is calculate the statistic given by :

$t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-3.833 -0}{\frac{3.763}{\sqrt{6}}}=-2.494$

The next step is calculate the degrees of freedom given by:

$df=n-1=6-1=5$

Now we can calculate the p value, since we have a left tailed test the p value is given by:

$p_v =P(t_{(5)}$

The p value is lower than the significance level assumed $\alpha=0.05$ , so then we can conclude that we can reject the null hypothesis. So we can say that the differences between Pretest and Posttest $\mu_{pretest}-\mu_{postest}$ are less than 0.

3 0

3 years ago

Z=5x-11y ?<br><br> and-2-5v < 8

velikii [3]

Answer:

Step-by-step explanation: v> -2 the > has a line under it

3 0

4 years ago

Pentagon ABCDE is dilated according to the rule

Tema [17]

The coordinates of A in the pre-image is (-1,2).

D0, 3(x,y) means (x,y) → (3x,3y)

A'(-3,6)
B'(-0.5, 8)
C'(2,6)
D'(1,3)
E'(-2,3)

The coordinates of the pre-image are multiplied by 3 resulting to the coordinates of the given image. So, we simply divide each value of x and y by 3 to get the coordinates of the pre-image.

A'(-3,6) → -3/3 = -1 ; 6/3 = 2 → A(-1,2)

6 0

3 years ago

Read 2 more answers