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Elza [17]
3 years ago
6

How do I find the inverse of the function? Also, is it a function and why?

Mathematics
1 answer:
yaroslaw [1]3 years ago
4 0

Answer:

Step-by-step explanation:

Essentially, begin by flipping the x and y terms:

x = (1 - 2y)^2 + 5

Then, solve for y:

\ x = (1-2y)^2 + 5\\\sqrt{x-5} = 1 - 2y\\\sqrt{x-5} - 1 = 2y\\\frac{\sqrt{x-5} - 1}{2} = y^-1\\

Because we know there is only 1 y-value for any given x-value, the inverse of the given function is also a function.

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