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4 years ago

Z=5x-11y ? and-2-5v < 8

Mathematics

1 answer:

velikii [3]4 years ago

3 0

Answer:

Step-by-step explanation: v> -2 the > has a line under it

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2 which of the following is a perfect cube<br> a) 400 -<br> D. 3375–<br> C 8000 -

allochka39001 [22]

Answer:

8000 is a perfect cube but 3375 can be also but i m a little sure that 8000 is a perfect cube

8 0

4 years ago

LaTeX: \sqrt[]{36} 36 2) LaTeX: \sqrt[3]{-8} − 8 3 3) LaTeX: -\sqrt[]{100} − 100 4) LaTeX: \sqrt[3]{27} I'm sorry that's the bes

Mamont248 [21]

Given:

Consider the expression are

1) $\sqrt{36}$

2) $\sqrt[3]{-8}$

3) $-\sqrt{100}$

4) $\sqrt[3]{27}$

To find:

The simplified form of each expression.

Solution:

1. We have,

$\sqrt{36}=\sqrt{6^2}$

$\sqrt{36}=6$

Therefore, the value of this expression is 6.

2. We have,

$\sqrt[3]{-8}=(-8)^{\frac{1}{3}}$

$\sqrt[3]{-8}=((-2)^3)^{\frac{1}{3}}$

$\sqrt[3]{-8}=(-2)^{\frac{3}{3}}$

$\sqrt[3]{-8}=-2$

Therefore, the value of this expression is -2.

3. We have,

$-\sqrt{100}=-\sqrt{10^2}$

$-\sqrt{100}=-10$

Therefore, the value of this expression is -10.

4. We have,

$\sqrt[3]{27}=(27)^{\frac{1}{3}}$

$\sqrt[3]{27}=(3^3)^{\frac{1}{3}}$

$\sqrt[3]{27}=(3)^{\frac{3}{3}}$

$\sqrt[3]{27}=3$

Therefore, the value of this expression is 3.

3 0

4 years ago

Can someone help me on this too!

Ann [662]

Answer:

72 signs

Step-by-step explanation:

90 min = 1.5 hour

6 hours hangs 6/1.5 * 18 signs = 72

3 0

3 years ago

Read 2 more answers

Subtract and simplify. Show work please!

ra1l [238]

1) Final expression: $+7y^2-6y-17$

2) Final expression: $21x^3-46x^2+59x-30$

Step-by-step explanation:

The first expression is

$(-2y^2-11y-7)-(-9y^2-5y+10)$

First, we remove the 2nd bracket by changing the sign of all the terms inside:

$-2y^2-11y-7-+9y^2+5y-10$

Now we group the terms with same degree together:

$(-2y^2+9y^2)+(-11y+5y)+(-7-10)$

Now we solve the expression in each brackets:

$(-2y^2+9y^2)+(-11y+5y)+(-7-10)=\\+7y^2-6y-17$

So, this is the final expression.

The second expression is

$(7x-6)(3x^2-4x+5)$

We apply the distributive property, so we rewrite the expression as follows:

$(7x-6)(3x^2-4x+5)=7x(3x^2-4x+5)-6(3x^2-4x+5)$

Solving both brackets,

$7x(3x^2-4x+5)-6(3x^2-4x+5)=\\21x^3-28x^2+35x-18x^2+24x-30$

Now we group terms of same degree together:

$21x^3-28x^2+35x-18x^2+24x-30=\\21x^3+(-28x^2-18x^2)+(35x+24x)-30$

And solving each bracket,

$21x^3+(-28x^2-18x^2)+(35x+24x)-30=\\21x^3-46x^2+59x-30$

So, this is the final expression.

Learn how to simplify expressions:

brainly.com/question/7014769

brainly.com/question/11007572

brainly.com/question/11334714

#LearnwithBrainly

3 0

3 years ago

Prove that√P is irrational for any prime number P

Luda [366]

Answer:

Step-by-step explanation:

I’m not sure if this is super accurate, but since P is prime, the only factors it has is 1 and itself, meaning that the square root of it will be irrational

3 0

3 years ago