Answer:
3/4
Step-by-step explanation:
A: students present
B: students on time
P(all students present and on time) = P(A and B) = 3/10
P(all students present) = P(A) = 2/5
P(A and B) = P(A).P(B|A) where P(B|A) is the probability of everyone being on time given that everyone is present
So P(B|A) = P(A and B) /P(A) = 3/10 ÷ 2/5 = 3/10 * 5/2 = 15/20 which can be reduced to 3/4 by dividing numerator and denominator by 5
Answer:
The probability that neither is available when needed
Step-by-step explanation:
A town has 2 fire engines operating independently
Given data the probability that a specific engine is available when needed is 0.96.
Let A and B are the two events of two fire engines
given P(A and B) = 0.96 ( given two engines are independent events so you have to select A and B)
Independent events : P( A n B) = P(A) P(B)
The probability that neither is available when needed
A. 8/$12=21/$x then cross multiply.
B. 1/$1.5
Answer:
y=x, x-axis, y=x, y-axis
Explanation:
Reflecting the figure across three axes just moves it from one quadrant to another. It does not map the figure to itself.
Reflecting across the line y=x moves it from quadrant II to IV or vice-versa. If it is in quadrant I or III, it stays there. So the sequence of reflections x-axis (moves from I to IV), y=x (moves from IV to II), x-axis (moves from II to III), y=x (stays in III) will not map the figure to itself.
However, the last selection will map the figure to itself. The initial (and final) figure location, and the intermediate reflections are shown in the attached. The figure starts and ends as blue, is reflected across y=x to green, across x-axis to orange, across y=x to red, and finally across y-axis to blue again.
Answer:
<u>Quadrant 2</u> (a.k.a. quadrant II)
Step-by-step explanation:
Think: in which quadrant are the x-values negative and the y-values positive?
( - , + ) <em>2</em> | (+, +) <em>1</em>
________|__________
( -, -) <em>3</em> | (+, -) <em>4</em>