Answer:
Name a transversal - i
Name all corresponding angles -
6 = 8
1 = 3
2 = 4
5 = 7
Name all alternate exterior angles -
1 = 5
4 = 8
Average rate of change can be calculated by determining the
rate of change at x = a, and at x = b
f’(x) =2 (3^x) ln(3)
f’(0) = 2 ln(3)
f’(1) = 6 ln(3)
f’(2) = 18 ln(3)
f’(3) = 54 ln(3)
Average:
at section A = [6 ln(3) – 2 ln(3)]/1 = 4 ln(3)
at section B = [54 ln(3) – 18 ln(3)]/1 = 36 ln(3)
section B is 9 times larger.
Based from the f’(x), f’(x) varies as the power of x. so the
greater of value of x, the greater the rate of change.
Answer:
19
Step-by-step explanation:
note that
(a + b)² = a² + b² + 2ab , that is
a² + b² + 2ab = (a + b)² ← subtract 2ab from both sides
a² + b² = (a + b)² - 2ab
= 5² - 2(3)
= 25 - 6
= 19
A bc it makes the most sence
