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diamong [38]
3 years ago
12

An equation that involves a multiplication addition, contains a variable, and has a solution of 8.

Mathematics
1 answer:
yulyashka [42]3 years ago
7 0
A variable is an unknown like x so 

first we start with 
x=8
then we subtract (because you must add to reverse subtraction)
x-2=8-2
x-2=6
then we divide ( because you must multiply to reverse division)
(x-2)/3=6/3
(x-2)/3=2

find x
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4 0
3 years ago
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Luba_88 [7]

Answer:

y=5,902,060*(.957)^t

Step-by-step explanation:

Since the original amount would be decreasing and it's an exponential one, hence the "every year", we can determine that it's an exponential decay equation.

The exponential delay equation is y=A*(1-r)^t. The y is the remaining amount, A is the original amount, r is the rate in decimal form, and t is for years. "1-r" is for decreasing rates and "1+r" is for increasing rates.

First thing we need to do is turn the rate, 4.3%, from a percentage to a decimal. You can do this by moving the decimal two places to the right, which gives you 0.043.

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y=5,902,060*(.957)^t

3 0
3 years ago
You use pemdas and they both equal to 77. So yes they are equivalent.
spayn [35]

Answer:

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7 0
3 years ago
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Ann [662]

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Step-by-step explanation:

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6 0
2 years ago
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