Question

Write the equation of the line that passes through the points (3, 7) and (-1, 2)

Answer 1

Answer:

$y = \frac{5}{4} x + 3 \frac{1}{4}$

Step-by-step explanation:

The equation of a line is usually written in the form of y=mx+c, where m is the gradient and c is the y-intercept.

Let's find the gradient of the line, m, first.

Gradient=$\frac{y1 - y2}{x1 - x2}$

$m = \frac{7 - 2}{3 - ( - 1)} \\ m = \frac{5}{3 + 1} \\ m = \frac{5}{4}$

$y = \frac{5}{4} x + c$

To find the value of c, substitute a coordinate.

when x= -1, y= 2,

$2 = \frac{5}{4} ( - 1) + c \\ c = 2 + \frac{5}{4} \\ c = 3 \frac{1}{4}$

Thus, the equation of the line is

$y = \frac{5}{4} x + 3 \frac{1}{4}$