The algebraic expression which represents the square of the difference of s and 6 is (s - 6)²
Step-by-step explanation:
Let us represent some words by mathematics expressions
- Square a number ⇒ x²
- Square the sum of two numbers ⇒ (x + y)²
- Sum of the squares of two numbers ⇒ x² + y²
- Square of difference of two numbers (x - y)²
- The difference of square two numbers x² - y²
∵ The expression is the square of the difference of s and 6
- That means find the difference between s and 6 at first,
then square the difference
∵ The difference of s and 6 = s - 6
- Square this difference means but the difference in a bracket
and then square the bracket
∴ The square of the difference = (s - 6)²
The algebraic expression which represents the square of the difference of s and 6 is (s - 6)²
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Answer 1:16 is the answer
Answer:
The rate at which Perimeter of the square is increasing is 
.
Step-by-step explanation:
Given:
Circumference of the circle = 
Rate of change of in circumference = 6 in/secs
We need to find the rate at which the perimeter of the square is increasing
Solution:
Now we know that;
Now we know that;
side of the square= diameter of the circle
side of the square = 
Now Perimeter of the square is given by 4 times length of the side.
Now we need to find the rate at which Perimeter is increasing so we will find the derivative of perimeter.
But 
So we get;
Hence The rate at which Perimeter of the square is increasing is .
Photo has an answer for you
Answer:
C- 27
Step-by-step explanation:
Y varies directly as X
Y=kx
K is a constant
12=k16
K=12/16=3/4
Y=3/4x
Y=3/4 (36)
Y=27
