Solution:
The standard equation of a hyperbola is expressed as

Given that the hyperbola has its foci at (0,-15) and (0, 15), this implies that the hyperbola is parallel to the y-axis.
Thus, the equation will be expressed in the form:

The asymptote of n hyperbola is expressed as

Given that the asymptotes are

This implies that

To evaluate the value of h and k,
Answer:
128
Step-by-step explanation:
There are 32 50's in 1600.
So 32x4=128
Answer:
−6x+18
Step-by-step explanation:
-6(x-3)
(−6)(x+−3)
=(−6)(x)+(−6)(−3)
=−6x+18
The second one on the top right