Find the next two terms in the given sequence, then write it in recursive form. A.) {7,12,17,22,27,...} B.) { 3,7,15,31,63,...}
iren [92.7K]
Answer:
A) a_n = 5n + 2
B) a_n = (2^(n + 1)) - 1
Step-by-step explanation:
A) The sequence is given as;
{7,12,17,22,27,...}
The differences are:
5,5,5,5.
This is an arithmetic sequence following the formula;
a_n = a_1 + (n - 1)d
d is 5
Thus;
a_n = a_1 + (n - 1)5
Now, a_1 = 7. Thus;
a_n = 7 + 5n - 5
a_n = 5n + 2
B) The sequence is given as;
{ 3,7,15,31,63,...}
Now, let's write out the differences of this sequence:
Differences are:
4, 8, 16, 32
This shows that it is a geometric sequence with a common ratio of 2.
In the given sequence, a_1 = 3 and a_2 = 7 and a_3 = 15
Thus, a_2 = 2a_1 + 1
Also, a_(2 + 1) = 2a_2 + 1
Combining both equations, we can deduce that: a_(n + 1) = 2a_n + 1
Thus; a_n can be expressed as:
a_n = (2^(n + 1)) - 1
Answer:
Step-by-step explanation:
1.
I think the pictures can be matched to the name without knowing the name when a person has already gotten familiar with other works from the particular country or region. Over time, we tend to subconsciously name and or identify things we're seeing for the first time due to having previous knowledge about what something that's closely related to it looks like.
2.
I think yes, it has good community contributions because they have put their respective countries out on the map due to their fantastic artwork. Without these designs, we might not have known the places as much as we do know them now.
The first one, decreasing then increasing
I believe the answer is B. Hope this helps :)
Answer:
a) 1.
Step-by-step explanation:
Supongamos que el primer número entero positivo es a tal que a ∈ Z⁺.
Luego, el conjunto de los cinco enteros positivos se puede expresar como
A = {a; a+1; a+2; a+3; a+4}
Dada la condición del problema, se debe cumplir que
a + (a+1) + (a+2) = (a+3) + (a+4)
⇒ 3a + 3 = 2a + 7
Resolviendo la ecuación resulta
a = 4
Luego, el conjunto A nos resulta
A = {4; 5; 6; 7; 8}
Puede concluirse que sólo un conjunto cumple con esta condición.