Inupt values for y and evaluate to get y values
(x,y)
if x=0
y=3(0)-1
y=0-1
y=-1
(0,-1)
if x=1
y=3(1)-1
y=3-1
y=2
(1,2)
if x=2
y=3(2)-1
y=6-1
y=5
(2,5)
if x=3
y=3(3)-1
y=9-1
y=8
(3,8)
look for the points
(0,-1) (1,2) (2,5) (3,8)
B
Answer:
Number of tickets sold in advance = 310
Number of tickets sold at the door = 340
Step-by-step explanation:
Note: This question is not complete. The complete question is therefore provided before answering the question as follows:
For the school play, the advance tickets cost $3, while tickets at the door cost $5. Thirty more tickets were sold at the door than in advance, and $2630 was collected. How many of each kind of ticket were sold?
The explation of the answer is now given as follows:
Let a represents number of tickets sold in advance. Therefore, we have:
a = number of tickets sold in advance at $3 each
a + 30 = number of tickets sold at the door at $5 each
The total amount collected can be represented by this equation:
3a + 5(a + 30) = 2630
Solving for a, wee have:
3a + 5a + 150 = 2630
8a = 2630 - 150
8a = 2,480
a = 2,480 / 8
a = 310
Therefore, this implies:
Number of tickets sold in advance = 310
Number of tickets sold at the door = a + 30 = 310 + 30 = 340
Answer:
A' (4,4), B' (5,7), C' (9,7)
Step-by-step explanation:
