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ivanzaharov [21]
3 years ago
15

Which square root is between four and five?

Mathematics
1 answer:
wolverine [178]3 years ago
6 0

Answer:

but the answer is that all real numbers greater than 16 and less than 25 would have square roots between 4 and 5.

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YOU WILL BE MARKED BRAINEIST PLESE HELP
Lubov Fominskaja [6]
I think b...i’m wrong pretty sure..
6 0
3 years ago
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Joe went to the hobby shop and bought 2 sport cars at %8.95 each and some paints.If he spent a total of %23.65,What was the coas
sweet-ann [11.9K]

I'm assuming that % means $:

8.95*2 = 17.9

23.65 - 17.9 =  5.74

The cost of the paint was $5.74

7 0
3 years ago
Please I need some help!
Schach [20]

(f+g)(x) = 8x+2

(f-g)(x) = 4x-6

Step-by-step explanation:

Given

f(x) =6x-2\\g(x)=2x+4

we have to find

<u>a. (f+g)(x)</u>

(f+g)(x)=f(x)+g(x)\\=(6x-2)+(2x+4)\\=6x-2+2x+4\\=6x+2x-2+4\\=8x+2

<u>b. (f-g)(x)</u>

(f-g)(x)=f(x)-g(x)\\=(6x-2)-(2x+4)\\=6x-2-2x-4\\=6x-2x-2-4\\=4x-6

Hence,

(f+g)(x) = 8x+2

(f-g)(x) = 4x-6

Keywords: Functions, Operations on Functions

Learn more about functions at:

  • brainly.com/question/4021035
  • brainly.com/question/4034547

#LearnwithBrainly

7 0
3 years ago
A large electronic office product contains 2000 electronic components. Assume that the probability that each component operates
KIM [24]

Answer:

The probability is 0.971032

Step-by-step explanation:

The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.

The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}

In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:

P(x)=\frac{2000!}{x!(2000-x)!}*0.005^{x}*(0.995)^{2000-x}     (eq. 1)

So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:

P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)

We can also calculated that as:

P(x ≥ 5) = 1 - P(x ≤ 4)

Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)

Then, if we calculate every probability using eq. 1, we get:

P(x ≤ 4) = 0.000044 + 0.000445 + 0.002235 + 0.007479 + 0.018765

P(x ≤ 4) = 0.028968

Finally, P(x ≥ 5) is:

P(x ≥ 5) = 1 - 0.028968

P(x ≥ 5) = 0.971032

3 0
3 years ago
How do you set up the combined probability of selecting a yellow hair clip, putting it back and then selecting a blue hair clip
Olegator [25]

Answer:

By separating

Step-by-step explanation:

3 0
3 years ago
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