The distance from the external point ^2 = The external segment of the secant * the full length of the secant.
tangent distance = 6
External portion of the secant = 3
Full length of the secant = x + 3
6^2 = 3*(x + 3) Remove the brackets.
36 = 3x + 9 Subtract 9 from both sides.
36 - 9 = 3x
27 = 3x Divide by 3
x = 9 <<<<<<<Answer.
First, you square numbers and multiply the exponents.
32^2 is 1024 and 6x2=12
4^2 is 16 and 4x2=8
The equation is now 1024m^12/16n^8
You divide the numbers and get 64
Since the m and n aren’t the same letter, you leave them alone
The answer is 64m^12n^8
2nd and 4th are functions
an x value in a set of functions can only have one y value. however, a y value can have infinite amount of x values
in the 1st and 3rd set, the x value of -2 has 2 y values
