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Radda [10]
3 years ago
10

In a circle with a radius of 3 ft, an arc is intercepted by a central angle of 2π/3 radians. What is the length of the arc?

Mathematics
2 answers:
Yuliya22 [10]3 years ago
7 0
(2/3) PI radians = 120 degrees
If radius is 3 feet then circumference = 2* PI * 3 =
<span> <span> <span> 18.8495559215 </span> </span> </span> feet
120 degrees is (1/3) of a circle so the arc length = <span>18.8495559215 / 3 =
</span> <span> <span> <span> 6.2831853072  </span> </span> </span>feet

Source:
http://www.1728.org/radians.htm


Andrej [43]3 years ago
6 0

Answer:

Hence, the arc length is 2π feet or 6.28 feet.

Step-by-step explanation:

In a circle with a radius of 3 ft, an arc is intercepted by a central angle of 2π/3 radians.

If the central angle is measured in degrees than the arc length is given by:

arc length=(θ\360°)×2πr.

and if central angle is measured in radians than the arc length is given by:

arc length=θr. ( where r is the radius of the circle)

where θ is the central angle.

Hence, here we have:

r= 3 ft.

and θ=2π/3.

Hence the arc length is given by:

Arc length=(2π/3)×3=2π  feet.

Hence, the arc length is 2π feet or 2×3.14=6.28 feet.

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Step-by-step explanation:

Given :

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s = 80 mph

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Refer to the accompanying technology display. The probabilities in the display were obtained using the values of n equals n=5 an
zubka84 [21]

Answer:

<u><em></em></u>

  • <u><em>Yes, it is reasonable to expect that more than one subject will experience​ headaches</em></u>

Explanation:

Notice that where it says "assume that 55 subjects are randomly selected ..." there is a typo. The correct statement is "assume that 5 subjects are randomly selected ..."

You are given the table with the probability distribution, assuming, correctly, the binomial distribution with n = 5 and p = 0.732.

  • p = 0.732 is the probability of success (an individual experiences headaches).
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The meaning of the table of the distribution probability is:

The probability that 0 subjects experience headaches is 0.0014; the probability that 1 subject experience headaches is 0.0189, and so on.

To answer whether it <em>is reasonable to expect that more than one subject will experience​ headaches</em>, you must find the probability that:

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That is:

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That is also the complement of P(X = 0) or P(X = 1)

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From the table:

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Hence:

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That is very close to 1; thus, it is highly likely that more than 1 subject will experience headaches.

In conclusion, <em>yes, it is reasonable to expect that more than one subject will experience​ headaches</em>

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