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Lapatulllka [165]
2 years ago
15

Whats the anwser to -3(x-9)=-3

Mathematics
1 answer:
Delvig [45]2 years ago
7 0

Step-by-step explanation:

-3x + 27= -3

-3x = -3-27

-3x = -30

x= 10

You might be interested in
Chain complete 40% of her homework on Monday and 2/3 on Tuesday if she started her homework on Monday what fractional part of he
kotykmax [81]

Answer:

1/5

Step-by-step explanation:

For Monday

The fraction of homework Chain completed =

40% of her homework

= 40% = 40/100

= 2/5

For Tuesday

The amount of home work left =

= 1 - 2/5

3/5

The fraction of homework Chain completed on Tuesday = 2/3

= 2/3 Of 3/5

= 2/3 × 3/5

= 2/5

Let the total complete homework be represented by 1

Hence:

The Fractional part of her homework left for her to complete after Tuesday =

1 - (2/5 + 2/5)

Lowest common denominator is 5

= 1 - (2 + 2/5)

= 1 - (4 /5)

= 1/5

8 0
2 years ago
How do I multiply at 9/25×1/6
bekas [8.4K]

Answer:

3/50

Step-by-step explanation:

It's not as hard as you might think! You can just multiply the denominator and numerators separately. So in this case, you just need to do 9*1 and 25*6. This means that the answer is just 9/150, simplify it and you get, 3/50!

4 0
3 years ago
Janice swam in the 400​ ___ backstroke.
ruslelena [56]
Meter/ yard. Likely meter since that is high/college standard
7 0
3 years ago
Which of the following are examples of random samples? Select all that apply?
prohojiy [21]
I think all solution apply
3 0
3 years ago
Can someone help me
erik [133]

Answer:

   6 < x < 23.206

Step-by-step explanation:

To properly answer this question, we need to make the assumption that angle DAC is non-negative and that angle BCA is acute.

The maximum value of the angle DAC can be shown to occur when points B, C, and D are on a circle centered at A*. When that is the case, the sine of half of angle DAC is equal to 16/22 times the sine of half of angle BAC. That is, ...

  (2x -12)/2 = arcsin(16/22×sin(24°))

  x ≈ 23.206°

Of course, the minimum value of angle DAC is 0°, so the minimum value of x is ...

  2x -12 = 0

  x -6 = 0 . . . . . divide by 2

  x = 6 . . . . . . . add 6

Then the range of values of x will be ...

  6 < x < 23.206

_____

* One way to do this is to make use of the law of cosines:

  22² = AB² + AC² -2·AB·AC·cos(48°)

  16² = AD² + AC² -2·AD·AC·cos(2x-12)

The trick is to maximize x while satisfying the constraints that all of the lengths are positive. This will happen when AB=AC=AD, in which case the equations be come ...

  22² = 2·AB²·(1-cos(48°))

  16² = 2·AB²·(1 -cos(2x-12))

The value of AB drops out of the ratio of these equations, and the result for x is as above.

4 0
3 years ago
Read 2 more answers
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